Evaluate H(t)=-20+11t H(11)=

Mathematics

2 answers:

ohaa [14]3 years ago

7 0

Answer:

H(11) = 101

Step-by-step explanation:

H(t) = -20 + 11t

H(11) = -20 + 11(11)

= -20 + 121

= 121 - 20

= 101

H(11) = 101

damaskus [11]3 years ago

4 0

Answer:

H(11)=101

Step-by-step explanation:

The function we have is:

$H(t)=-20+11t$

and we need to find the value of

$H(11)$

this is evaluating the function $H(t)$ when the value of t is $t=11$

So, first we substitute $t=11$ in H(t):

$H(11)=-20+11(11)$

we solve the expression:

$H(11)=-20+121\\H(11)=101$

the answer is that when $t=11$ , the function has the value $H(11)=101$

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given the two points (-24,7) and (30,25) a. What is an equation passing through the points? b. Is (51, 33) also on the same line

kicyunya [14]

Part 1) Given the two points (-24,7) and (30,25) a. What is an equation passing through the points?

step 1
find the slope m
m=(y2-y1)/(x2-x1)---->m=(25-7)/(30+24)----> m=18/54----> m=1/3

step 2
wit m=1/3 and the point (30,25)
find the equation of the line
y-y1=m*(x-x1)-----> y-25=(1/3)*(x-30)--->y=(1/3)*x-10+25
y=(1/3)*x+15

the answer Part 1) is
y=(1/3)*x+15

Part 2) Is (51, 33) also on the same line?
if the point (51.33) is on the line y=(1/3)*x+15
then
for x=51 the value of y must be 33
for x=51
y=(1/3)*51+15----> y=17+15----> y=32
32 is not 33
so
the point does not belong to the given line

the answer Part 2) is
the point does not belong to the given line

see the attached figure