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slava [35]
3 years ago
13

If the ordinate is three more than twice the abscissa and x {-1, 0, -1/3}, which of the following sets of ordered pairs satisfie

s the given conditions?
A. {(-1, 1), (0, 3), (-1/3, 7/3)}
B. {(-1, 1), (0, 3), (-1/3, 11/3)}
C. {(-1, -1), (0, 3), (-1/3, 1)}
Mathematics
2 answers:
Molodets [167]3 years ago
8 0

Answer:

c

Step-by-step explanation:

lions [1.4K]3 years ago
7 0

Answer:

I think it is A not sure though

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245. 202, 254, 245, 276<br>Write the values from least to<br>greatest<br>Mean<br>Median:<br>Mode:​
Burka [1]

Answer:

The values from least to greatest would be 202, 245, 245, 254, 276

The mean would be 244.4

The median would be 245

The mode would be 245

Step-by-step explanation:

To find the mean, you add all the numbers together and divide that sum by the number of numbers. In this case, you add all the numbers together and you get 1222. Next, you divide that by 5 because there are 5 numbers. To find the median, you order the numbers from least to greatest and find the middle number. For this question, the answer would be 245. Lastly, to find the mode you look for the number that appears the most. In this case it's 245.

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Answer:

discriminant =0

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Step-by-step explanation:

The discriminant is b^2 -4ac  

when the equation is written in the form  ax^2 +bx+c

f(x) = 3x^2 +24x+48

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discriminant = 24^2 - 4(3)*(48)

                      =576-576

                        =0


If the discriminant >0  we have 2 real roots

if discriminant = 0  we have 1 real root

if discriminant <0 we have 2 complex roots

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Step-by-step explanation:

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