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3 years ago

Why is it important to record audio of silence in the area in which you are filming?

Computers and Technology

2 answers:

Trava [24]3 years ago

5 0

Answer:

That depends. The answer I would give is so if something does arise, such as a really big noise accompanied by a really big animal, then you'd have more than just video. If a natural disaster occurs, the only way to tell may be through audio.

Serhud [2]3 years ago

3 0

Answer:

To make sure that there is no other outside/excess noise while you are filming your actual film

Hoped this helped !

Cheers, Z

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mixas84 [53]

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4 years ago

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tekilochka [14]

What's the question your asking here cause I'd be happy to answer it.

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3 years ago

You are asked by your supervisor to export NPS configuaration from a server. Your supervisor contacts you and tells you it is mi

Vesna [10]

Answer:

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3 years ago

write a program to evaluate the following postfix expression. the value of each variable must be asked from the user during the

ikadub [295]

In this exercise we have to use the knowledge of computational language in C++ to write a code that program to evaluate the following postfix expression. the value of each variable must be asked from the user during the execution time.

<h3>Writting the code:</h3>

#include <bits/stdc++.h>

using namespace std;

// CREATED A CLASS STACK

class Stack

{

public:

int top;

unsigned sz;

int* ar;

};

// VARIOUS STACK FUNCTIONS

Stack* makeStack( unsigned sz )

{

Stack* stack = new Stack();

// BASE CONDITION

if (!stack) return NULL;

stack->top = -1;

stack->sz = sz;

stack->ar = new int[(stack->sz * sizeof(int))];

if (!stack->ar) return NULL;

// RETURNING THE STACK

return stack;

}

// CHECKING IF THE STACK IS EMPTY

int isEmpty(Stack* stack)

{

return stack->top == -1 ;

}

// CHECKING THE TOP OF THE STACK

int whatAtTop(Stack* stack)

{

return stack->ar[stack->top];

}

// POPPING OUT OF A STACK

int pop(Stack* stack)

{

if (!isEmpty(stack))

return stack->ar[stack->top--] ;

return '$';

}

// PUSHING IN THE STACK

void push(Stack* stack, int op)

{

stack->ar[++stack->top] = op;

}

// EVALUATING POSTFIX STARTS HERE

int postfixEvaluator(string res)

{

// CREATING STACK

Stack* stack = makeStack(res.length());

int i;

// BASE CONDITION

if (!stack) return -1;

for (i = 0; res[i]; ++i)

{

// CHECK FOR SPACES

if (res[i] == ' ')continue;

// CHECK FOR THE DIGIT

else if (isdigit(res[i]))

{

int N = 0;

// EXTRACT THE NUMBER OUT OF STACK

while (isdigit(res[i]))

{

N = N * 10 + (int)(res[i] - '0');

i++;

}

i--;

// PUSH THE NUMBER IN STACK

push(stack, N);

}

// POPPING AND ARITHMETIC OPERATIONS

else

{

int pos1 = pop(stack);

int pos2 = pop(stack);

switch (res[i])

{

case '+': push(stack, pos2 + pos1); break;

case '-': push(stack, pos2 - pos1); break;

case '*': push(stack, pos2 * pos1); break;

case '/': push(stack, pos2 / pos1); break;

}

return pop(stack);

}

// MAIN CODE

int main()

{

string tes;

getline(cin, tes);

string tmp = "";

string res = "";

for (int i = 0; i < tes.length(); i++) {

if (tes[i] <= 'z' and tes[i] >= 'a') {

tmp += tes[i];

} else if (tes[i] == ' ' and (tes[i - 1] <= 'z' and tes[i - 1] >= 'a')) {

cout << "Enter the value of " << tmp << ": ";

int x; cin >> x;

res += (to_string(x));

res += ' ';

tmp = "";

} else {

res += tes[i];

}

cout << "\nThe postfix expression is : " << res;

cout << "\nThe result is : " << postfixEvaluator(res);

return 0;

}

See more about C++ at brainly.com/question/19705654

#SPJ1

8 0

1 year ago

Write a Python program that creates a dictionary containing course numbers and the room numbers of the rooms where the course me

alisha [4.7K]

Answer:

Following are the program in the Python Programming Language:

#set dictionary

rooms ={}

rooms.update({'CS101' : 3004})

rooms.update({'CS102' : 4501})

rooms.update({'CS103' : 6755})

rooms.update({'NT110' : 1244})

rooms.update({'CM241' : 1411})

#set dictionary

instructors={}

instructors.update({'CS101' : 'Haynes'})

instructors.update({'CS102' : 'Alvarado'})

instructors.update({'CS103' : 'Rich'})

instructors.update({'NT110' : 'Burke'})

instructors.update({'CM241' : 'Lee'})

#set dictionary

time={}

time.update({'CS101' : '8:00 a.m'})

time.update({'CS102' : '9:00 a.m'})

time.update({'CS103' : '10:00 a.m'})

time.update({'NT110' : '11:00 a.m'})

time.update({'CM241' : '1:00 p.m'})

while True:

n=input("You want to continue(y/n): ")

if(n=="n"):

break

else:

cours=input('Enter a course number: ')

try:

print()

print("Room Number: ", rooms[cours])

print("Instructors: ",instructors[cours])

print("Meeting time: ", time[cours])

except KeyError:

print("Invalid")

Output:

You want to continue(y/n): y

Enter a course number: CS101

Room Number: 3004

Instructors: Haynes

Meeting time: 8:00 a.m

You want to continue(y/n): y

Enter a course number: NT1244

Invalid

You want to continue(y/n): y

Enter a course number: NT110

Room Number: 1244

Instructors: Burke

Meeting time: 11:00 a.m

You want to continue(y/n): n

Explanation:

Here we define three dictionary type variables "rooms", "instructors", "time"

and assign value in these dictionaries by the update() method.

Then, we set the while loop inside it:

set a variable "n" and get input from the user.
set the if conditional statement and pass the condition is the variable "n" is equal to the value "n" then, loop is break otherwise,
we get an input from the user in the variable "cours" and apply try block inside it, we print "room number", "Instructor", "Meeting time" as given in the output and in except block it print "Invalid".

6 0

3 years ago