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Ket [755]
3 years ago
5

which process( photosynthesis, cellular respiration, both) do algae preform when incubated in the light? in the dark?

Biology
2 answers:
ExtremeBDS [4]3 years ago
6 0

Answer:

In light algae performs both photosynthesis and cellular respiration.

Algae performs only Calvin Cycle of photosynthesis when kept in dark.

Explanation:

Algae is a multi-cellular organism or unicellular organism which is capable of performing photosynthesis. It contains the pigment chlorophyll which is used to trap sunlight which converts carbon dioxide and water.

Cellular respiration also takes place in the algae and it is a continuous process that takes place all the time.

In case of dark or when there is no light only Calvin Cycle take place.

otez555 [7]3 years ago
5 0

Answer:

  • Algae preform both photosynthesis and cellular respiration when incubated in the light.
  • Algae preform only Calvin cycle of photosynthesis and cellular respiration when incubated in the dark.

Explanation:

Algae do perform photosynthesis and cellular respiration during light just like other plant specie. They use chlorophyll a or b as pigments to collect light energy and drive the process of photosynthesis.

We know that photosysnthesis is basically a two step process i.e light reactions and dark reactions (dark reaction is also called Calvin cycle). So, in dark algae only performs Calvin cycle and shuts off the light harvesting steps of photosynthesis. However, cellular respiration keeps going throughout the life of algae without being affected. We can say that algae share these characteristics with the green plants.

Hope it helps! :)


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Volgvan

Answer:

0.153

Explanation:

We know the up-thrust on the fish, U = weight of water displaced = weight of fish + weight of air in air sacs.

So ρVg = ρ'V'g + ρ'V"g where ρ = density of water = 1 g/cm³, V = volume of water displaced, g = acceleration due to gravity, ρ'= density of fish = 1.18 g/cm³, V' = initial volume of fish, ρ"= density of air = 0.0012 g/cm³ and V" = volume of expanded air sac.

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ρ(V' + V") = ρ'V' + ρ"V"

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V'/V" = (ρ - ρ")/(ρ' - ρ)

= (1 g/cm³ - 0.0012 g/cm³)/(1.18 g/cm³ - 1 g/cm³)

= (0.9988 g/cm³ ÷ 0.18 g/cm³)

V'/V" = 5.55

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V/V" = 6.55

V"/V = 1/6.55

V"/V = 0.153

So, the fish must inflate its air sacs to 0.153 of its expanded body volume

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3 years ago
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