The value of P(4, 6) when the two number cubes are tossed is 1/36
<h3>How to determine the probability?</h3>
On each number cube, we have:
Sample space = {1, 2, 3, 4, 5, 6}
The individual probabilities are then represented as:
P(4) =1/6
P(6) =1/6
The value of P(4, 6) when the two number cubes are tossed is:
P(4, 6) = P(4) * P(6)
This gives
P(4, 6) = 1/6 * 1/6
Evaluate
P(4, 6) = 1/36
Hence, the value of P(4, 6) when the two number cubes are tossed is 1/36
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Cos(t/2) I got .45 is that what you were looking for or do I need to plug it into the equation up top? can you give me notes of something? cos( -9/11/2) = .45
Answer:
225%
Step-by-step explanation:
1. Divide the new weight by the original weight.
90/40 = 2.25.
2. Multiply by 100 to get the percentage.
2.25 x 100 = 225%
9 x 0.55 = 4.95, which can be rounded to the ones place.
5 books remain.
Answer:
I think A
Step-by-step explanation:
With the equasions shown A makes the most sense
