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Papessa [141]
3 years ago
7

Pedro simplified four over seven divided by five over eight.; his work is shown below. Identify where he made his error. Origina

l division problem: four over seven divided by five over eight. Step 1: four over seven multiplied by eight over five. Step 2: four times five over seven times eight. Step 3: twenty over fifty-six. Step 4: five over fourteen.
Mathematics
2 answers:
Triss [41]3 years ago
6 0
He  cross multiplied when he should've multiplied straight across...

<span>Original division problem: four over seven divided by five over eight
</span>
step one: f<span>our over seven multiplied by eight over five</span>

step two: 4*8=32    7*5=35

32/35
Vlad [161]3 years ago
5 0
Step 3 is wrong.
It should be 4/7 / 5/8
                    4/7 x 8/5
                    32/ 35

                    
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Is -3 a natural number a whole number a integer a rational number or irrational number
BaLLatris [955]

Answer:

-3 is a rational integer.

Step-by-step explanation:

An integer is a superset of the whole numbers that includes the negated values as well as 0.

A rational number is simply anything that can be expressed as a fraction.

-3 is by these definitions, a negated 3, and any non fractional number can be expressed as a fraction.

-3 is not a natural number, as that is the set of numbers {1, 2, 3, 4, 5, ... etc} and -3 is not a whole number, as that is the set of numbers {0, 1, 2, 3, 4, ... etc}.

And -3 is also not an irrational number since it can be expressed as a fraction.

Thus, -3 is a rational integer.

Cheers.

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3 years ago
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2 = 58m cubed

3 = 140m cubed

4 = 180in cubed

Step-by-step explanation:

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2 years ago
29.24/0.153 is what?
PolarNik [594]

Answer:

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3 years ago
Suppose the following number of defects has been found in successive samples of size 100: 6, 7, 3, 9, 6, 9, 4, 14, 3, 5, 6, 9, 6
Brut [27]

Answer:

Given the data in the question;

Samples of size 100: 6, 7, 3, 9, 6, 9, 4, 14, 3, 5, 6, 9, 6, 10, 9, 2, 8, 4, 8, 10, 10, 8, 7, 7, 7, 6, 14, 18, 13, 6.

a)

For a p chart ( control chart for fraction nonconforming), the center line and upper and lower control limits are;

UCL = p" + 3√[ (p"(1-P")) / n ]

CL = p"

LCL = p" - 3√[ (p"(1-P")) / n ]

here, p" is the average fraction defective

Now, with the 30 samples of size 100

p" =  [∑(6, 7, 3, 9, 6, 9, 4, 14, 3, 5, 6, 9, 6, 10, 9, 2, 8, 4, 8, 10, 10, 8, 7, 7, 7, 6, 14, 18, 13, 6.)] / [ 30 × 100 ]

p" = 234 / 3000

p" = 0.078

so the trial control limits for the fraction-defective control chart are;

UCL = p" + 3√[ (p"(1-P")) / n ]

UCL = 0.078 + 3√[ (0.078(1-0.078)) / 100 ]

UCL = 0.078 + ( 3 × 0.026817 )

UCL = 0.078 + 0.080451

UCL = 0.1585

LCL = p" - 3√[ (p"(1-P")) / n ]

LCL = 0.078 - 3√[ (0.078(1-0.078)) / 100 ]

LCL = 0.078 - ( 3 × 0.026817 )

LCL = 0.078 - 0.080451

LCL =  0 ( SET TO ZERO )

Diagram of the Chart uploaded below

b)

from the p chart for a) below, sample 28 violated the first western electric rule,

summary report from Minitab;

TEST 1. One point more than 3.00 standard deviations from the center line.

Test failed at points: 28

Hence, we conclude that the process is out of statistical control

Lets Assume that assignable causes can be found to eliminate out of control points.

Since 28 is out of control, we should eliminate this sample and recalculate the trial control limits for the P chart.

so

p" = 0.0745

UCL = p" + 3√[ (p"(1-P")) / n ]

UCL = 0.0745 + 3√[ (0.0745(1-0.0745)) / 100 ]

UCL = 0.0745 + ( 3 × 0.026258 )

UCL = 0.0745 + 0.078774

UCL = 0.1532

LCL  = p" - 3√[ (p"(1-P")) / n ]

LCL = 0.0745 - 3√[ (0.0745(1-0.0745)) / 100 ]

LCL = 0.0745 - ( 3 × 0.026258 )

LCL = 0.0745 - 0.078774

UCL = 0  ( SET TO ZERO )

The second p chart diagram is upload below;

NOTE; the red circle symbol on 28 denotes that the point is not used in computing the control limits

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2 years ago
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Tom [10]
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3 years ago
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