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Gemiola [76]
4 years ago
9

If a 42.9ft tall flagpole casts a 253.1 ft long shadow, then how long is the shadow that a 6.2ft tall woman casts?

Mathematics
1 answer:
natali 33 [55]4 years ago
3 0
The women's shadow would be 36.6ft. long. 
You have to set up a proportion   42.9             6.2
                                                       ---------   =   ------------ 
                                                        253.1               X
Then you cross multiply (6.2*253.1) and divide (1569.22/42.9) equals 36.6
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Find the lenght of side BC. give your answer to 3 significant figures
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Answer:

BC ≈ 19.4 cm

Step-by-step explanation:

Using the cosine ratio in the right triangle

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BC × cos71° = 6.3 ( divide both sides by cos71° )

BC = \frac{6.3}{cos71} ≈ 19.4 cm ( to 3 significant figures )

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3 years ago
Please help me! STU is an equilateral triangle. If ST is one less than twice x, SU is 37 less than five times x, and TU is 11 mo
zhuklara [117]

Answer:

x = 12

ST = 23 units

SU = 23 units

TU = 23 units

Step-by-step explanation:

For an equilateral triangle, all the angles are equal. Also, all the sides are equal.

Hence given that the sides ST is one less than twice x, SU is 37 less than five times x, and TU is 11 more than x

ST = 2x - 1

SU = 5x - 37

TU = x + 11

Since ST = SU = TU

2x - 1 = 5x - 37

collect like terms

37 - 1 = 5x - 2x

36 = 3x

Divide both  3

36/3 = x

x = 12

Therefore

ST = 2x - 1 = 2(12) - 1 = 23 units

SU = 5x - 37 = 5(12) - 37 = 23 units

TU = x + 11 = 12 + 11 = 23 units

8 0
3 years ago
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Answer:

A

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18÷100

=18% 18 of 100 that means 18/100

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