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AlekseyPX
3 years ago
9

Farmer Fran would like to build a chicken coop in order to raise chickens and sell their eggs. She determines that the area of t

he length of the coop must be a minimum of 300 ft. If the length of the coop is 12 feet, then how wide does the chicken coop need to be?
Mathematics
1 answer:
Maru [420]3 years ago
5 0

Answer:

The chicken coops needs to be atleast 25 feet in width.


Step-by-step explanation:

The chicken coop is in a shape of a rectangle.

Area of rectangle is given by length * width


Since, length is given as 12 ft and area is given as minimum 300 ft, the width can be found by substituting these values into the area formula:

Area=Length*Width\\300=12*Width\\Width=\frac{300}{12}=25


The chicken coops needs to be atleast 25 feet in width.

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A conservative estimate of the number of stars in the universe is 6 x 10^22. The average human can see about 3,000 stars at nigh
Ilia_Sergeevich [38]

2 \times 10^{19} times more stars are there in universe compared to human eye can see

<h3><u>Solution:</u></h3>

Given that, conservative estimate of the number of stars in the universe is 6 \times 10^{22}

The average human can see about 3,000 stars at night with only their eyes

To find: Number of times more stars are there in the universe, compared to the stars a human can see

Let "x" be the number of times more stars are there in the universe, compared to the stars a human can see

Then from given statement,

\text{Stars in universe} = x \times \text{ number of stars human can see}

<em><u>Substituting given values we get,</u></em>

6 \times 10^{22} = x \times 3000\\\\x = \frac{6 \times 10^{22}}{3000}\\\\x = \frac{6 \times 10^{22}}{3 \times 10^3}\\\\x = 2 \times 10^{22-3}\\\\x = 2 \times 10^{19}

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4 years ago
PLEASE HELP I RLLY DONT KNOW WHAT TO DO
Jlenok [28]

Answer:

a) f(0) = -9

b) f(2) = -5

c) f(-3) = -15

d) f(1/2)=-8

Step-by-step explanation:

We are given the function f(x)=2x-9 and we need to find the following:

a) f(0)

For finding f(0) put x =0 in the given function

f(x)=2x-9\\Put\:x=0\\f(0)=2(0)-9\\f(0)=-9

So, we get f(0)=-9

b) f(2)

For finding f(2) put x =2 in the given function

f(x)=2x-9\\Put\:x=2\\f(2)=2(2)-9\\f(2)=4-9\\f(2)=-5

So, we get f(2)=-5

c) f(-3)

For finding f(-3) put x =-3 in the given function

f(x)=2x-9\\Put\:x=-3\\f(-3)=2(-3)-9\\f(-3)=-6-9\\f(-3)=-15

So, we get f(-3)=-15

d) f(1/2)

For finding f(1/2) put x =1/2 in the given function

f(x)=2x-9\\Put\:x=\frac{1}{2}\\f(\frac{1}{2})=2(\frac{1}{2})-9\\f(\frac{1}{2})=1-9\\f(\frac{1}{2})=-8

So, we get f(1/2)=-8

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3 years ago
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