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viktelen [127]
3 years ago
5

PLS ANSWER ASAP

Mathematics
1 answer:
rosijanka [135]3 years ago
4 0

Answer:

7/16

Step-by-step explanation:

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(d) A car travels at an average speed of 80 km/h. How far does it travel in: (1) 2 hours? (11) 12 minutes?​
zepelin [54]
Answer is (1) 160 km in 2 hours and
(2) 16 miles in 12 minutes.

Step by step.
80 km / 1 hour = x km /2 hours
Cross multiply =
x = 160

The second one requires a little more math. Because we are looking at how far in minutes, we change the rate of 80km in 1 hour to 80 km in 60 minutes.
80 km / 60 = x / 12
Cross multiply
12x = 960
Solve for x by dividing both sides by 12
X = 16

I did the math on a print screen to explain the cross multiply.

3 0
1 year ago
J.J.Bean sells a wide variety of outdoor equipment and clothing. The company sells both through mail order and via the internet.
melamori03 [73]

Answer:

99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

Step-by-step explanation:

We are given that a random sample of 16 sales receipts for mail-order sales results in a mean sale amount of $74.50 with a standard deviation of $17.25.

A random sample of 9 sales receipts for internet sales results in a mean sale amount of $84.40 with a standard deviation of $21.25.

The pivotal quantity that will be used for constructing 99% confidence interval for true mean difference is given by;

                      P.Q.  =  \frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }  ~ t__n_1_+_n_2_-_2

where, \bar X_1 = sample mean for mail-order sales = $74.50

\bar X_2 = sample mean for internet sales = $84.40

s_1 = sample standard deviation for mail-order purchases = $17.25

s_2 = sample standard deviation for internet purchases = $21.25

n_1 = sample of sales receipts for mail-order purchases = 16

n_2 = sample of sales receipts for internet purchases = 9

Also,  s_p =\sqrt{\frac{(n_1-1)\times s_1^{2}+(n_2-1)\times s_2^{2} }{n_1+n_2-2} }  =  \sqrt{\frac{(16-1)\times 17.25^{2}+(9-1)\times 21.25^{2} }{16+9-2} } = 18.74

The true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is represented by (\mu_1-\mu_2).

Now, 99% confidence interval for (\mu_1-\mu_2) is given by;

             = (\bar X_1-\bar X_2) \pm t_(_\frac{\alpha}{2}_)  \times s_p \times \sqrt{\frac{1}{n_1} +\frac{1}{n_2}}

Here, the critical value of t at 0.5% level of significance and 23 degrees of freedom is given as 2.807.

          = (74.50-84.40) \pm (2.807  \times 18.74 \times \sqrt{\frac{1}{16} +\frac{1}{9}})

          = [$-31.82 , $12.02]

Hence, 99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

5 0
3 years ago
A water sprinkler sprays in a circular pattern a distance of 10 ft from the sprinkler to the edge. What is the circumference of
vfiekz [6]

Answer:

<h2>62.8 ft</h2>

Step-by-step explanation:

7 0
3 years ago
Please help please help
gogolik [260]
1. 9/44
2. 1/3
3. 1/14
4. 4/45
5. 7/12
6. 14/55
7. 5/12
8. 2/9
9. 1/16
10. 7/6
11. 5/12
12. 4/5
13. 6/7
14. 7/12
15. 1
16. 3/2
17. 15/8
18. 4/7
4 0
2 years ago
A conical perfume bottle has a radius of 3.2 centimeters and a height of 3.9 centimeters.
ioda

For this case, we must find the volume of the perfume bottle, given by the volume of a cone.

V = \frac {\pi * r ^ 2 * h} {3}

Where:

r: It's the radio

h: It's the height

Substituting the values:

V = \frac {3.14 * (3.2) ^ 2 * 3.9} {3}\\V = \frac {125.39904} {3}\\V = 41.79968 \ cubic \ centimeters

Round off:

V = 41.80 \ cubic \ centimeters

Thus, the bottle contains 41.80 cubic centimeters of perfume

Answer:

Option C

6 0
2 years ago
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