3 years ago

Logb121=2 Can somebody help and explain?

Mathematics

2 answers:

Tanzania [10]3 years ago

6 0

$log_b121=2\iff b^2=121\to b=\sqrt{121}\to b=11\\\\b > 0\ \wedge\ b\neq1\\\\\\\log_ab=c\iff a^c=b$

alexira [117]3 years ago

5 0

$log_b 121=2 \\ log_b 11^2=2 \\ 2log_b11=2 \\ log_b11=1$
therefore b=11

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