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Fiesta28 [93]
3 years ago
12

What would the ratio of the numbed of cans to the price at super saver

Mathematics
1 answer:
hammer [34]3 years ago
6 0
What r the numbers I can't help you out if I don't have the numbers
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What is the surface area?<br> 4 ft<br> 4 ft<br> 4 ft
Veronika [31]

The surface area of what shape exactly?

5 0
3 years ago
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PLEASE HELP ASAP!!! CORRECT ANSWERS ONLY PLEASE!!!
topjm [15]

Answer:  B. neither

<u>Step-by-step explanation:</u>

A function is even when f(x) = f(-x).

A function is odd when f(-x) = -f(x).


f(x) = 2x³ - x²

f(-x) = 2(-x)³ - (-x)²

      = -2x³ - x²

f(x) = 2x³ - x²     ≠    f(-x) = -2x³ - x²     so it is NOT EVEN


-f(x) = -(2x³ - x²)

      = -2x³ + x²

f(-x) = -2x³ - x²     ≠    -f(x)= -2x³ + x²     so it is NOT ODD  


Therefore, it is NEITHER even nor odd.

5 0
3 years ago
A journal article reports that a sample of size 5 was used as a basis for calculating a 95% CI for the true average natural freq
oksano4ka [1.4K]

Answer:

Lower = 231.134- 3.098=228.036

Upper = 231.134+ 3.098=234.232

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n=5 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

And for this case we know that the 95% confidence interval is given by:

\bar X=\frac{233.002 +229.266}{2}= 231.134

And the margin of error is given by:

ME = \frac{233.002 -229.266}{2}= 1.868

And the margin of error is given by:

ME= t_{\alpha/2} \frac{s}{\sqrt{n}}

The degrees of freedom are given by:

df = n-1 = 5-1=4

And the critical value for 95% of confidence is t_{\alpha/2}= 2.776

So then we can find the deviation like this:

s = \frac{ME \sqrt{n}}{t_{\alpha/2}}

s = \frac{1.868* \sqrt{5}}{2.776}= 1.506

And for the 99% confidence the critical value is: t_{\alpha/2}= 4.604

And the margin of error would be:

ME = 4.604 *\frac{1.506}{\sqrt{5}}= 3.098

And the interval is given by:

Lower = 231.134- 3.098=228.036

Upper = 231.134+ 3.098=234.232

6 0
3 years ago
Steps to solve: 28x - 12 + 2x - 4 - x
Musya8 [376]

Let's simplify by step

28x-12+2x-4-x

28x+-12+2x+-4+-x

Combine like terms

28x+-12+2x+-4+-x

(28x+2x+-x)+(-12+-4)

29x+-16

= 29x-16


I hope that's help !

8 0
3 years ago
Joexreader where are you Joexreader​
Anit [1.1K]

Answer:

this seems like an interesting story

4 0
3 years ago
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