This algebra one or two please mark me brainlist I need 1
Answer:
P= Rs 60000
A= Rs 79860
T=1 & 1/2 year = 3/2 years
= 3/2 x 2 = 3 half years
R= ?
Applying the formula A= P (1+r/100)^T
79860 = 60000 (1+ r/100)^3
79860/60000 = (1+r/100)^3
1331/1000 = (1+r/100)^3
root(3)(1331/1000) = (1+r/100)
11/10 = 1+r/100
11/10 -1 = r/100
1/10 = r/100
r= 10 %
Step-by-step explanation:
See the attachments for the answer :)
Answer:
The answer is below
Step-by-step explanation:
Speed is the time rate of change of velocity, it is the ratio of distance to time.
Mr. Fowles runs at a steady 4.2 miles per hour. The time taken to cover 26 miles is:
speed = distance / time
time = distance / speed = 26 / 4.2 = 6.19 hour
I run at 3 miles per hour. I was given 3 mile lead, so the remaining distance is 23 miles (26 - 3). The time needed to complete the 23 miles is:
time = distance / speed = 23 / 3 = 7.67 hour
a) Let d be the distance Mr Fowles catches me. Hence:
time = (d + 3)/4.2; also time = d/3
(d + 3)/4.2 = d/3
3d + 9 = 4.2d
1.2d = 9
d = 7.5 miles
He would catch me at 10.5 (7.5 + 3) miles from the starting point.
b) Mr. fowles finishes after 6.19 hour. At that time, the distance is have covered is:
distance = 6.19 * 3 mi/hr = 18.57 mile
Distance behind = 23 mile - 18.57 = 4.43 mile
c) time longer = 7.67 hour - 6.19 hour = 1.48 hour
Answer:
Step-by-step explanation:
let the horizontal distance be x
(17.8-1.5)/x = tan 38
or x = 16.3/tan38
or x = 20.863
