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Vilka [71]
3 years ago
11

Isabelle proves that the triangles are congruent by

Mathematics
2 answers:
skelet666 [1.2K]3 years ago
6 0

Answer:

C. ∠ABC ≅ ∠DCB; alternate interior angles of parallel lines are congruent

Step-by-step explanation:

I just took the test and got it right. Hope it helps!

Rudik [331]3 years ago
4 0

We cannot answer since we do not have the picture or diagram.

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Mark has no basketballs. cat has eight basketballs and Sophia has six balls how many do they have all together?
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14 because Mark has none, Cat has 8 and Sophia has 6 so 8+6=14.

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Convert 12.3 liters to milliliters.
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Answer:12300

Step-by-step explanation:12.3x1000

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Y=3x-8 in function notation
julia-pushkina [17]

To write it in function notation you'll convert it into a function, substituting y by f(x):


y = 3x - 8 = f(x) = 3x - 8



Hope it helped,



BioTeacher101

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Vertical angles are opposite angles with the same vertex <br> true or false
Sati [7]
True 
<span>Vertical angles are opposite angles with the same vertex </span>
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3 years ago
Evaluate the definite integral using the graph of f(x)<br> (Image included)
Tanya [424]

a) The first integral corresponds to the area under y = f(x) on the interval [0, 3], which is a right triangle with base 3 and height 5, hence the integral is

\displaystyle \int_0^3 f(x) \, dx = \frac12 \times 3 \times 5 = \boxed{\frac{15}2}

b) The integral is zero since the areas under the curve over [3, 4] and [4, 5] are equal but opposite in sign. In other words, on the interval [3, 5], f(x) is symmetric and odd about x = 4, so

\displaystyle \int_3^5 f(x) \, dx = \int_3^4 f(x) \, dx + \int_4^5 f(x) \, dx = \int_3^4 f(x) \, dx - \int_3^4 f(x) \, dx = \boxed{0}

c) The integral over [5, 9] is the negative of the area of a rectangle with length 9 - 5 = 4 and height 5, so

\displaystyle \int_5^9 f(x) \, dx = -4\times5 = -20

Then by linearity, we have

\displaystyle \int_0^9 f(x) \, dx = \left\{\int_0^3 + \int_3^5 + \int_5^9\right\} f(x) \, dx = \frac{15}2 + 0 - 20 = \boxed{-\frac{25}2}

8 0
2 years ago
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