Circle A is shown with a central angle marked 42 degrees and the radius marked 8 inches.

Mathematics

2 answers:

vodka [1.7K]3 years ago

7 0

Answer:

D. $\pi (8in)^{2}\times \frac{42}{360}$

Step-by-step explanation:

We are given that,

Radius of the circle = 8 inches

Central angle of the circle = 42°

As, we know,

Area of a sector of a circle = $\pi r^{2}\times \frac{\theta}{360}$

So, substituting the values, we get,

Area of a sector the circle = $\pi 8^{2}\times \frac{42}{360}$

Thus, option D i.e. $\pi (8in)^{2}\times \frac{42}{360}$ can be used to find the area of the sector.

kkurt [141]3 years ago

4 0

Answer:

Step-by-step explanation:

You might be interested in

Which of the following shows the best way to set up the product of (2x - 5) and<br> (4 - 3x + 4.)?

masha68 [24]

Answer:

Step-by-step explanation:

It usually works best to use the polynomial with fewer terms as the multiplier. A row of partial products is written for each term of the multiplier, so the fewer terms will result in fewer rows of partial products.

In order to keep like terms together, it is preferable to allocate a separate column of the multiplication tableau to each power of the operands or product. This means we want to make note of the fact that the cubic multiplicand has a coefficient of 0 for its x^2 term.

The best setup is the one shown in the attachment.