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Marizza181 [45]
3 years ago
11

PLZ HELP ANSWER FAST

Mathematics
1 answer:
mote1985 [20]3 years ago
4 0
The slope of a straight line can be calculated by
tan¶=y2-y1/x2-x1
tan¶= 0/-4
= 0

The slope is Zero.
You might be interested in
A race is 3 miles long. There are water stations every 3/4 mile along the route. How many water stations are along the route?
Vilka [71]
There will be 4 water stations.

Why?

3/4 = .75 as a decimal

Personally, I believe that it’s easier to use decimals, I can explain the way in fractions in the comments if you’d like, just ask.

Anyway, .75 • 4= 3

or 3 / .75 = 4 (division is easier with bigger numbers)

so, there will be 4 water stations, given that the one race is 3 miles long.

If this explanation seems unclear, I’d be happy to explain. Feel free to ask in the comments!! I’m happy to help.

Hope this helps!

(If you find this answer helpful, please consider marking me brainliest, Thanks!)
6 0
3 years ago
Shelby mixes a 25% bleach solution with 5 cups of a 10% bleach solution, resulting in a 20% bleach solution. The table shows the
german

Answer:

10

Step-by-step explanation:

We will use a system of equations to solve this.  We do not know how much of the 25% bleach solution is used; we will use x to represent this.  We know that 5 cups of the 10% solution was used.  We do not know how much of the resulting solution we have; we will use y to represent this.  This gives us the equation

x+5 = y

Using the decimal forms of the percentages for each solution, we have 0.25x (25% solution for x cups), 0.1(5) (10% solution for 5 cups) and 0.2y (20% solution for y cups); this gives us the equation

0.25x+0.1(5) = 0.2y

This gives us the system

\left \{ {{x+5=y} \atop {0.25x+0.1(5)=0.2y}} \right.

To use elimination, we will make the coefficients of x the same by multiplying the top equation by 0.25:

\left \{ {{0.25(x+5=y)} \atop {0.25x+0.5=0.2y}} \right. \\\\\left \{ {{0.25x+1.25=0.25y} \atop {0.25x+0.5=0.2y}} \right.

We will now subtract the second equation from the first:

\left \{ {{0.25x+1.25=0.25y} \atop {-(0.25x+0.5=0.2y)}} \right. \\\\0.75 = 0.05y

Divide both sides by 0.05:

0.75/0.05 = 0.05y/0.05

15 = y

There were 15 cups of the resulting 20% solution.  Substituting this into the first equation, we have

x+5=15

Subtract 5 from each side:

x+5-5=15-5

x = 10

7 0
3 years ago
Read 2 more answers
Will give brainliest answer
natita [175]
A translation by 11 units to the left and 3 units up
4 0
3 years ago
Please answer thanks! Brainliest
dimaraw [331]

Answer:

D - T-H is negative

Step-by-step explanation:

So lets go through what we know:

M is on the left side of 0, so M is negative.

A is also one the left side of 0, so A is negative.

T is on the right side of 0, so T is postive

H is also on the right side of 0, so H is postive

Lets go through each answer and see if it is accurate or not:

The sum of M and H is postive.

With what we know, M is negative and H is postive.

Looking at the graph, we can see that M is farther to the left than H is to the right.

So this means that M is a larger negative than H is postive, meaning when we add them together, the answer will be negative, not postive.

Next we have the answer to A divided by H is negative

We know A is negative, and M also negative

Remember, a negative divided or multiplied by a negative is postive.

This is not what our answer states, as it says it should be negative.

So next off, we have the product of H and A is postive.

Product means multipication.

A is negative and H is postive

Since it is multipication, and we know a negative and postive make another negative, this would make it incorrect

The answer states it must be postive, but this is negative.

Finally we have the answer as T-H is negative.

We see that T is postive, and H is postive.

T is less than H is, so when you subtract H from T, you would get a negative.

So D is the answer

Hope this helps!

4 0
3 years ago
Is 1 greater than 6/5
zzz [600]
No

Explanation: 6/5 is equivalent to 1 1/5
which is greater than 1, so 1 is less than 6/5
6 0
4 years ago
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