Question

A standard bowling ball cannot be more than 27 inches in circumference. What is the maximum volume of such a ball (to the nearest cubic inch) before the holes are drilled? ​

Answer 1

Answer:

333 in^3

Step-by-step explanation:

Circumference = pi *d

27 = pi*d

Replacing d with 2*r  ( 2 times the radius)

27 = pi * 2 * r

Divide each side by 2

27/2 = pi *r

13.5 = pi *r

Divide by pi

13.5/ pi = r

We want to find the volume of a sphere

V = 4/3 pi * r^3

V = 4/3 pi (13.5/pi)^3

  = 4/3 pi * (13.5)^3 / (pi^3)

  4/3 pi/pi^3  * (13.5)^3

   4/3 * 1/ pi^2 *2460.375

 3280.5 / pi^2

Let pi be approximated by 3.14

 380.5/(3.14)^2

 332.7214086 in^3

To the nearest in^3

333 in^3

Answer 2

Answer:

332.384142939 cubic inch, rounded- 332 cubic inches

Step-by-step explanation:

Volume of a sphere is 4/3 pi*r^3

circumference=C = 2 π r

we can simply 27 by 2*pi to get radius-

approx 4.29718346348.

4/3 pi*4.29718346348.^3

4/3* pi*79.3508690311= about 332.384142939