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damaskus [11]
3 years ago
12

Are the truss triangles ABD and BFC congruent? Which postulate did you use for your proof? Which engineer was correct?

Mathematics
1 answer:
Nesterboy [21]3 years ago
6 0
1)Yes
2) I think it’s Natalie who is right.
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|x-7|+5 is greater than or equal to 3
jonny [76]
\large\begin{array}{l} \textsf{Solve the absolute value inequality:}\\\\ \mathsf{|x-7|+5\ge 3}\\\\ \mathsf{|x-7|\ge 3-5}\\\\ \mathsf{|x-7|\ge -2}\\\\\\ \textsf{Since absolute values always give a non-negative number,}\\\textsf{every real value for x satisfies the inequatily:}\\\\ \textsf{For all }\mathsf{x\in\mathbb{R},}\\\\ \mathsf{|x-7|\ge 0>-2}\\\\\\ \therefore~~\mathsf{|x-7|\ge 2}\\\\ \textsf{regardless of the value of x.} \end{array}


\large\begin{array}{l} \textsf{Solution set: }\mathsf{S=\mathbb{R}.} \end{array}


If you're having problems understanding this answer, try seeing it through your browser: brainly.com/question/2180151


\large\textsf{I hope this helps. :-)}


Tags: <em>absolute value inequatily solve solution algebra</em>

6 0
3 years ago
Please Help!!!! Solve For L
Sonja [21]
<h3>Given :</h3>

  • \tt B = L - L a f

<h3>To Find :</h3>

  • L = ?

<h3>Solution :</h3>

\tt B = L - L a f

By taking L common from \tt (L - L a f), we get :

\tt : \implies B = L(1 - a f)

\tt : \implies \dfrac{B}{(1 - a f)} = L

\tt : \implies L = \dfrac{B}{1 - a f}

Hence, value of \tt L = \dfrac{B}{1 - a f}

4 0
3 years ago
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PLs help lots of points
NikAS [45]

Answer:

I believe it is cube A

Step-by-step explanation:

the volume of Cube B equaled 2073.6 in for me. so it would be less than cube A

4 0
3 years ago
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1)the difference between the upper and the lower quartile is the
nirvana33 [79]
A) interquartile range

The difference between the upper and the lower quartile is a measure of spread known as the interquartile range.
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3 years ago
WILL VOTE BRAINLIEST PLEASE HELP!
DanielleElmas [232]
A.) is the correct answer.
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3 years ago
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