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Neporo4naja [7]
3 years ago
14

Which expression is equivalent to 4/9(2n-3)

Mathematics
1 answer:
Andreyy893 years ago
5 0

Step-by-step explanation:

your answer is 8.9 and minus 11 by 3 means your answer is A

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The area for the square below is 49 inches. What is the measurement of
shutvik [7]

Answer:

7

Step-by-step explanation:

Area for a square is s² where 's' is a side (all sides have the same length)

6 0
3 years ago
A parallelogram with an area of 160.5 in has the height of measures 7.5 in find the length of the base
dimaraw [331]
To find the length of the base using the information given, you will use the formula for finding the area of a parallelogram and solve for the missing base.

A =bh
<u>160.5</u> = <u>7.5b</u>
7.5        7.5
b = 21.4 inches

The length of the base is 21.4 inches.
8 0
3 years ago
Read 2 more answers
Arizona has 15 counties how many do Florida and Georgia have
Lynna [10]

Answer:

Florida has 67 counties, Georgia has 159.

<em>Hope this helps :)</em>


7 0
3 years ago
The measure of an angle is 8 degrees less than three times the measure another angle. If the two angles are supplementary, what
slamgirl [31]
Small angle - x
large angle - 3x-8
supplementary = sum of this angles = 180
x+3x-8=180
4x-8=180
4x=188
x=47  
large angle  3x-8=3*47-8= 133°
check: 133+47=180



3 0
3 years ago
How do you find the area of something if you are given three different numbers?
Mice21 [21]
First notice that we are finding the area of the trapezoid.
The area of a trapezoid is:
\frac{1}{2}h(b_1 + b_2), 
where h is the height, b₁ and b₂ being the bases of the trapezoid. 
But before we find the area we have to find the side length of the third side in the triangle. To find this, we need to use the Pythagorean Theorem. 
a^{2} +b^{2} = c^{2}
(3.3)^{2} + b^{2} = (3.6)^{2}
When we solve this equation, we obtain 1.4387, which I will round to 1.4. 
Now, we use the area formula. The side length of the bottom base is 1.4 + 7 = 8.4. 
Plugging into the formula we get:\frac{1}{2}(3.3)(8.4 + 1.8) =  16.83
4 0
4 years ago
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