<h3>
Answer: 28</h3>
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Explanation:
Method 1
Imagine a table with 8 rows and 8 columns to represent all possible match-ups. You can actually draw out this table or just think of it as a thought experiment.
There are 8*8 = 64 entries in the table. Along the northwest diagonal, we have each team pair up with itself. This is of course silly and impossible. We cross off this entire diagonal so we drop to 64-8 = 56 entries.
Then notice that the lower left corner is a mirror copy of the upper right corner. A match-up like AB is the same as BA. So we must divide by 2 to get 56/2 = 28 different matches.
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Method 2
There are 8 selections for the first slot, and 8-1 = 7 selections for the second slot. We have 8*7 = 56 permutations and 56/2 = 28 combinations.
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Method 3
Use the nCr combination formula with n = 8 and r = 2
There are 28 combinations possible. Order doesn't matter (eg: match-up AB is the same as match-up BA).
Notice how the (8*7)/2 expression is part of the steps shown above in the nCr formula.
If
1 bushel = 48 pounds
and 1 pound = 3 apples
48 pounds = x apples cross multiply
x apples = 48 X 3 ==> 144 apples
1 bushel = 144 apples (because 48 pounds = 1 bushel)
315 bushel = x apples
x apples = 144 X 315
x = 45360 apples
Answer:
3 ÷ 8
Step-by-step explanation:
1. A fraction has two parts: a numerator and a denominator. The numerator is the dividend (the number that is to be divided by the divisor), and the denominator is the divisor (the number that is divided into the dividend).
2. Given the information above, we know that 3 is the numerator, and 8 is the denominator. This means 3 ÷ 8 = 3/8.
Answer: If the original equation is y = 3x -4, the slope is 3.
Any equation of a line parallel to the line <u>y = 3x -4</u> will have a slope of 3.
Step-by-step explanation:
In slope-intercept form, y =mx + b the coefficient of x, m is the slope.
Here 3 is that value.
It is very unusual to have two equal signs in a question about slope.
I am not sure what to do with the <u><em>=8y + 1</em></u>
Is this supposed to be another equation in the system, missing a term?
I hope you figure the problem out