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hjlf
3 years ago
8

What's the approximate area of 10 cm around a circle ?

Mathematics
1 answer:
bonufazy [111]3 years ago
6 0
<span>To find the circumference of a circle, you use the formula, pi x diameter. Pi=3.14. The diameter is not given to you in the question but we know that radius is half of diameter. So 10 times 2=20. Diameter =20. </span><span> multiply pi and the diameter. 3.14 x 20=62.8.   </span>62.8 cm is your circumference
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y= 3(5)x

Step-by-step explanation:

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What is the y-intercept of the polynomial f(x)f(x) defined below? Write the y-value only. f(x)=-4x^2+x^5+10x^3+5x+8x^4
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370 College freshmen were interviewed. 200 were registered for an Advanced Math class. 270 were registered for an English class
frozen [14]

Answer:

Step-by-step explanation:

To aid in understanding, draw three circles...

100 were registered for both Math and English.

50 were registered for both Sport and English but not Math.

70 were registered for Math, Sport, and English.

From here we will be able to calculate for those that signed up for only English class: Total number of students that signed up for english class

a. none signed up only for Maths (refer to attached document)

b. How many signed up for neither Math nor English meaning they signed up for only sports which is 70 from the venn diagram in the attachment.

c. How many signed up for an English class and at least one other class?

From the venn diagram:

we could have an English class and maths class - 100

we could also have an a English class and sports - 50

Thus total is 150.

d. What is the total fee for all the students enrolled in classes

From the diagram, 120 (english only and sport only) enrolled for only one class = 120 x $100 = $12,000

From the diagram, 180 (english and sport, maths and sport and english and maths) enrolled for two classes = 180 x $150 = $27,000

From the diagram, only 70 enrolled for the three classes = 70 x $200 = $14,000

Total fees = $12,000 + $27,000 + $14,000 = $53,000

5 0
3 years ago
A survey of 35 people was conducted to compare their self-reported height to their actual height. The difference between reporte
monitta

Answer:

The test statistic is t = 3.36.

Step-by-step explanation:

You're testing the claim that the mean difference is greater than 0.7.

At the null hypothesis, we test if it is 0.7 or less, that is:

H_0: \mu \leq 0.7

At the alternate hypothesis, we test if it is greater than 0.7, that is:

H_1: \mu > 0.7

The test statistic is:

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, s is the standard deviation and n is the size of the sample.

0.7 is tested at the null hypothesis:

This means that \mu = 0.7

Survey of 35 people. From the sample, the mean difference was 0.95, with a standard deviation of 0.44.

This means that n = 35, X = 0.95, s = 0.44

Calculate the test statistic

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{0.95 - 0.7}{\frac{0.44}{\sqrt{35}}}

t = 3.36

The test statistic is t = 3.36.

7 0
3 years ago
after spending 7/9 of a three hours examination, a student left the exams hall. How many minutes has he to complete the duration
Montano1993 [528]
40 mins left! total time= 60 mins x 3 hours =180 mins. 180 divided by 9 is 20. 20 times 7 is 140. 180-140 equals 40. yay!
6 0
3 years ago
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