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3 years ago

Y = 5x – 1

Mathematics

2 answers:

erastova [34]3 years ago

5 0

Answer:

Option 1 - There is one solution : (0,-1)

Step-by-step explanation:

Given : The system of equations $y=5x-1$ and $-15x-3y=3$

To find : How many solutions does this linear system have?

Solution :

Let Equation (1), $y=5x-1$

Equation (2), $-15x-3y=3$

Applying substitution method,

Substitute y from equation (1) into (2),

$-15x-3y=3$

$-15x-3(5x-1)=3$

$-15x-15x+3=3$

$-30x=0$

$x=0$

Substitute in equation (1),

$y=5x-1$

$y=5(0)-1$

$y=-1$

Therefore, There is one solution : (0,-1)

So, Option 1 is correct.

AnnyKZ [126]3 years ago

3 0

Y=5x-1
-15x-3y=3
-15x-15x+3=3
-30x=0
x=0
therefore y=5x0 -1= -1
so one solution(0,-1)

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The temperature of a certain solution is estimated by taking a large number of independent measurements and averaging them. The

Mademuasel [1]

Answer:

(a) The 95% confidence interval for the temperature is (36.80°C, 37.20°C).

(b) The confidence level is 68%.

(d) The 95% confidence interval for the temperature if 10 measurements were made is (36.93°C, 37.07°C).

Step-by-step explanation:

Let X = temperature of a certain solution.

The estimated mean temperature is, $\bar x=37^{o}C$ .

The estimated standard deviation is, $s=0.1^{o}C$ .

(a)

The general form of a (1 - α)% confidence interval is:

$CI=SS\pm CV\times SD$

Here,

SS = sample statistic

CV = critical value

SD = standard deviation

It is provided that a large number of independent measurements are taken to estimate the mean and standard deviation.

Since the sample size is large use a z-confidence interval.

The critical value of z for 95% confidence interval is:

$z_{0.025}=1.96$

Compute the confidence interval as follows:

$CI=SS\pm CV\times SD\\=37\pm 1.96\times 0.1\\=37\pm0.196\\=(36.804, 37.196)\\\approx (36.80^{o}C, 37.20^{o}C)$

Thus, the 95% confidence interval for the temperature is (36.80°C, 37.20°C).

(b)

The confidence interval is, 37 ± 0.1°C.

Comparing the confidence interval with the general form:

$37\pm 0.1=SS\pm CV\times SD$

The critical value is,

CV = 1

Compute the value of P (-1 < Z < 1) as follows:

$P(-1$

The percentage of z-distribution between -1 and 1 is, 68%.

Thus, the confidence level is 68%.

(c)

The confidence interval for population mean can be constructed using either the z-interval or t-interval.

If the sample selected is small and the standard deviation is estimated from the sample, then a t-interval will be used to construct the confidence interval.

But this will be possible only if we assume that the population from which the sample is selected is Normally distributed.

Thus, the necessary assumption is that the population is normally distributed.

(d)

For n = 10 compute a 95% confidence interval for the temperature as follows:

The (1 - α)% t-confidence interval is:

$CI=\bar x\pm t_{\alpha/2, (n-1)}\times \frac{s}{\sqrt{n}}$

The critical value of t is:

$t_{\alpha/2, (n-1)}=t_{0.025, 9}=2.262$

*Use a t-table for the critical value.

The 95% confidence interval is:

$CI=37\pm 2.262\times \frac{0.1}{\sqrt{10}}\\=37\pm 0.072\\=(36.928, 37.072)\\\approx (36.93^{o}C, 37.07^{o}C)$

Thus, the 95% confidence interval for the temperature if 10 measurements were made is (36.93°C, 37.07°C).

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Write the equation 9y = 12x + 0.2 in standard form. Identify A, B, and C.

uysha [10]

Answer:

A = -12, B = 9 and C = .2

Step-by-step explanation:

So it just looks like we need to use algebra to move everything around to get it in the form Ax + By = C

So, let's start with 9y = 12x + 0.2. From standard form we have all terms wth variables on one side, so let's do that. the right sie has both a variable term and non variable term, so let's get rid of the variable term. The variable term is 12x, so to get rid of it you subtract 12x from both sides.

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9y - 12x = 0.2

To make it exactly in standard form just rarrnge.

-12x + 9y = 0.2

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Answer:

x = 16°

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Step-by-step explanation:

Since the whole figure is 180°

Deduct 180 by the numbers mentioned above in order to find x.

180 - 2 - 9 - 9 = 160

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