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sweet-ann [11.9K]
3 years ago
13

1. Combine the expressions(a) 7x+3+6x +11​

Mathematics
1 answer:
navik [9.2K]3 years ago
6 0
13x+14. Combine like terms (7x+6x=13x) (3+11=14)
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6. Find the measure of each<br> marked angle.
Katyanochek1 [597]
ANSWER : both angles are 60 degrees and x is equal to 8.
10x - 20 = 7x + 4
Move the terms
3x = 24
x= 8
Sub back in to find the value:
80 - 20 = 60
56 + 4 = 60

Please mark as brainliest
8 0
3 years ago
√secA+tanA/√secA-tanA × √cosecA-1/√cosecA+1=1
Snowcat [4.5K]

Use:\\\\\sec A=\dfrac{1}{\cos A}\\\\\tan A=\dfrac{\sin A}{\cos A}\\\\\csc A=\dfrac{1}{\sin A}\\\\\sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\\sqrt{\dfrac{a}{b}}=\dfrac{\sqrt{a}}{\sqrt{b}}\\---------------------------------\\\\\sec A+\tan A=\dfrac{1}{\cos A}+\dfrac{\sin A}{\cos A}=\dfrac{1+\sin A}{\cos A}\\\\\sec A-\tan A=\dfrac{1-\sin A}{\cos A}\\\\\csc A-1=\dfrac{1}{\sin A}-\dfrac{\sin A}{\sin A}=\dfrac{1-\sin A}{\sin A}\\\\\csc A+1=\dfrac{1+\sin A}{\sin A}


\dfrac{\sqrt{\sec A+\tan A}}{\sqrt{\sec A-\tan A}}\cdot\dfrac{\sqrt{\cos A-1}}{\sqrt{\cos A+1}}=1\\\\L_s=\sqrt{\dfrac{\sec A+\tan A}{\sec A-\tan A}\cdot\dfrac{\cos A-1}{\cos A+1}}=\sqrt{\dfrac{\frac{1+\sin A}{\cos A}}{\frac{1-\sin A}{\cos A}}\cdot\dfrac{\frac{1-\sin A}{\sin A}}{\frac{1+\sin A}{\sin A}}}\\\\=\sqrt{\dfrac{1+\sin A}{\cos A}\cdot\dfrac{\cos A}{1-\sin A}\cdot\dfrac{1-\sin A}{\sin A}\cdot\dfrac{\sin A}{1+\sin A}}\\\\\text{Everything are simplified}\\\\=\sqrt{1}=1=R_s

7 0
3 years ago
Find the measure of x and y
zysi [14]

Answer:

y - 41°

x - ?

Step-by-step explanation:

use method of Z equation

Z 41° so y is 41° too

make sense

8 0
3 years ago
GIVING 20 POINTS<br> If a=4 b=8 c=2 d=7 e=3 f=9 g=10<br> What does bc-c³ equal?
kozerog [31]

Answer:

8

Step-by-step explanation:

b=8

c=2

(8)(2)-(2)^3 =  16-8  =8

6 0
4 years ago
Read 2 more answers
If the area of the circle is 206.1 m², find the radius. Round your answer to the nearest
densk [106]

Answer:

D) 8.1 m

Step-by-step explanation:

Area of a circle is pi r^2

5 0
3 years ago
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