There's only one step to solve this problem (that's if you're looking for it)
Because,
The coordinates of the vertices of the image are L' = (-4, 6), M' = (-5, 1) and N' = (-7, 3)
<h3>What are the coordinates of the vertices of the image?</h3>
The vertices of the preimage of the triangle are given as:
L = (4, -6)
M = (5, -1)
N = (7, -3)
The rotation is given as: 180 degrees counterclockwise
<h3 />
The rule of this rotation is
(x, y) => (-x, -y)
So, we have:
L' = (-4, 6)
M' = (-5, 1)
N' = (-7, 3)
Hence, the coordinates of the vertices of the image are L' = (-4, 6), M' = (-5, 1) and N' = (-7, 3)
Read more about rotation at:
brainly.com/question/4289712
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Move the decimal right 3 times
Answer:
32 degrees
Step-by-step explanation: So they tell you BE is congruent to BC so triangle BCE is isosceles. We know that angle C is 35 degrees and the triangle is isosceles so angle E is 35 degrees too. Now we do 180-(35+35) and that equals 110 so angle B is 110. And we know that angle EBC and FBA are supplementary angles so 180-110 is 70 degrees so angle FBA is 70 degrees and you can do the same thing with angle DFB and AFB so 180-102 degrees is 78 degrees and to find angle a you just do 180-(70+78) and that equals 32 degrees so angle A is 32 degrees. :)
Answer:
Step-by-step explanation:
Square the 10.
Subtract 10 with 5.
Multiply the numbers in the numerator.
Divide 1000 with 100.
