Find three consecutive even numbers who’s sum is 60.

Mathematics

2 answers:

kati45 [8]3 years ago

6 0

Answer:

18,20,22

Step-by-step explanation:

18,20,22 are consecutive even numbers that sum to equal 60.

alekssr [168]3 years ago

6 0

<h3>Answer: The three numbers are 18, 20, 22</h3>

==========================================================

Explanation:

Consecutive numbers are numbers like {4,5,6}, so they are numbers that follow right after another. Consecutive even numbers are numbers like {4,6,8} meaning they are even and follow one after another.

Let,

x = some even number

x+2 = next even number after x

x+4 = next even number after x+2

Add up the numbers mentioned, set the sum equal to 60, and solve for x.

(x)+(x+2)+(x+4) = 60

x+x+2+x+4 = 60

(x+x+x)+(2+4) = 60

3x+6 = 60

3x = 60-6

3x = 54

x = 54/3

x = 18 is the first even number

x+2 = 18+2 = 20 is the next even number

x+4 = 18+4 = 22 is the third even number

As a check,

18+20+22 = 60

which confirms our answer.

You might be interested in

Two cards are selected from a standard deck of 52 playing cards. The first card is not replaced before the second card is select

Blizzard [7]

Answer:

Probability is: $\frac{\textbf{13}}{\textbf{51}}$

Step-by-step explanation:

From a deck of 52 cards there are 26 black cards. (Spades and Clubs).

Also, there are 26 red cards. (Hearts and Diamonds).

First, we determine the probability of drawing a black card.

P(drawing a black card) = $\frac{number \hspace{1mm} of \hspace{1mm} black \hspace{1mm} cards}{total \hspace{1mm} number \hspace{1mm} of \hspace{1mm} cards}$ $= \frac{26}{52} = \frac{\textbf{1}}{\textbf{2}}$

Now, since we don't replace the drawn card, there are only 51 cards.

But the number of red cards is still 26,

∴ P(drawing a red card) = $\frac{number \hspace{1mm} of \hspace{1mm} red \hspace{1mm} cards}{total \hspace{1mm} number \hspace{1mm}of \hspace{1mm} cards}$ $= \frac{26}{51}$