You need to put the x or y value in the other equation ;
For example excersize a
It given that
Y=x^2+3x-1
Then you put it on the first equation :
x+x^2+3x-1=4
And then you solve it
x+x^2+3x-1-4=0
4x+x^2-5=0
We will make the order to seem easier
x^2+4x-5=0
x1=-5
x2=1
Then you put the x1,2 that you found on the second equation :
y=(-5)^2+3*(-5)-1=9
y=1^2+3*1-1=3
For summary :
x1=-5
x2=1
y1=9
y2=3
Hey there!
<u>Solve </u><u>for </u><u>f</u><u> </u><u>:</u>
f = 27.9 ✅
<em>></em><em> </em><em>Given </em><em>expression </em><em>:</em><em> </em>

<em>></em><em> </em><em>Multiply </em><em>both </em><em>sides </em><em>by </em><em>9</em><em> </em><em>:</em>

Therefore, our answer is f = 27.9
▪️Learn more about <em>first-degree </em><em>equations</em><em>:</em><em> </em>
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Idk if i'm exactly right but i think it's 500.73
Answer:
Solve for
x
by simplifying both sides of the equation, then isolating the variable.
Step-by-step explanation:
is this solve for x? you can just tell me what you are doing with this ex: adding, etc