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Anettt [7]
3 years ago
15

What is the value of u? 6.4u−5.1u=−3.25 Enter your answer in the box. u=

Mathematics
2 answers:
Ymorist [56]3 years ago
8 0

6.4u-5.1u=-3.25 subtract

1.3u=-3.25  divide

u= -2.5

Nastasia [14]3 years ago
8 0

Answer:

The answer is u=-2.5

Step-by-step explanation:

This exercise consists in clear the value of u, so we will have to made a subtraction and a division, this is:

6.4u-5.1u=-3.25\\Subtracting\\1.3u=-3.25\\Dividing\\u=\frac{-3.25}{1.3} \\u=-2.5

From the above the answer is u=-2.5

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Using the graph below, what are the common ratio and the general term equation, an, of the geometric sequence?
Len [333]
Given that the geometric series is given by:
an=a1(r)^(n-1)
where:
a1= first term
r=common ratio
n=number of terms:
from the graph, our sequence is:
-32,-24,-18,...
where:
a1=-32
a2=-24
a3=-18
thus
common ratio, r=-24/-32=3/4

thus the general form will be:
an=-32(3/4)^(n-1)

3 0
3 years ago
I need help someone plz help me
Grace [21]
5) -4+(-3) = -7 because you got -4 and then 3 more negatives so you got 7 negatives

6) -3+2= -1 because you got -3 and then 2 positives , now you have only one negative left

7)5+(-3) = 2 because you have 5 pozitives and then 3 negatives happen, now you got only 2 positives remaining...and so on
5 0
3 years ago
Read 2 more answers
3
iren2701 [21]

Answer:

B

D

A

Step-by-step explanation:

Given:

A. 2x^3-x^{2} -6x

B. 2x^3+8x+4

C. 3x^4+x^{2} +x-7

D. 3x^4-3x^{2} +5x-7

Now, let us evaluate the given expressions one by one.

(4x^3-4+ 7x)-(2x^3-x-8)\\\Rightarrow 4x^3-4+ 7x-2x^3+x+8\\\Rightarrow 2x^3+8x+ 4

It is equation B.

So, (4x^3-4+ 7x)-(2x^3-x-8) is equivalent to B.

(-3x^2+x^4+x)+(2x^4-7+4x)\\\Rightarrow -3x^2+x^4+x+2x^4-7+4x\\\Rightarrow3x^4-3x^{2} +5x-7

It is equation D.

So, (-3x^2+x^4+x)+(2x^4-7+4x)  is equivalent to D.

(x^{2} -2x)(2x+3)\\\Rightarrow 2x^3-4x^{2} +3x^{2} -6x\\\Rightarrow 2x^3-x^{2} -6x

It is equation A.

So, (x^{2} -2x)(2x+3) is equivalent to A.

So, answer is:

B

D

A

8 0
3 years ago
Given that BZ BA, if WV = 24, find ZY.<br> A. 48<br> B. 24<br> C. 12<br> D. 6
lions [1.4K]

The computation shows that the value of the length of ZY will be B. 24.

<h3>How to illustrate the information?</h3>

Let the assumed figures be:

BZ = 48

BA = 12

WV = 24

ZY = Unknown

Let's assume that the opposite sides in the quadrilateral are the same, the value of ZY will be:

ZY = (48 × 12)/24

ZY = 24

Learn more about length on:

brainly.com/question/2217700

#SPJ1

5 0
2 years ago
The half-life of the isotope Osmium-183 is 12 hours. Choose the equation below that gives the remaining mass of Osmium-183 in gr
raketka [301]

The given equations are incomprehensible, I'm afraid...

You're given that osmium-183 has a half-life of 12 hours, so for some initial mass <em>M</em>₀, the mass after 12 hours is half that:

1/2 <em>M</em>₀ = <em>M</em>₀ exp(12<em>k</em>)

for some decay constant <em>k</em>. Solve for this <em>k</em> :

1/2 = exp(12<em>k</em>)

ln(1/2) = 12<em>k</em>

<em>k</em> = 1/12 ln(1/2) = - ln(2)/12

Now for some starting mass <em>M</em>₀, the mass <em>M</em> remaining after time <em>t</em> is given by

<em>M</em> = <em>M</em>₀ exp(<em>kt </em>)

So if <em>M</em>₀ = 590 g and <em>t</em> = 36 h, plugging these into the equation with the previously determined value of <em>k</em> gives

<em>M</em> = 590 exp(36<em>k</em>) = 73.75

so 73.75 ≈ 74 g of Os-183 are left.

Alternatively, notice that the given time period of 36 hours is simply 3 times the half-life of 12 hours, so 1/2³ = 1/8 of the starting amount of Os-183 is left:

590/8 = 73.75 ≈ 74

6 0
3 years ago
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