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Thepotemich [5.8K]
2 years ago
13

The ticket price for a concert at a historic music hall includes $6.70 for the concert $4.20 for the program and a hall restorat

ion fee. The price for 19 tickets is $223.25. How much is the restoration fee?
Mathematics
1 answer:
bonufazy [111]2 years ago
4 0

let the restoration fee to be X

we dont need 19 tickets right ?? we just need one for you :--)

So, 223.25/19 = $11.75 <----( the price for your single ticket.

since this is the whole thing for concert, program and restoration fees

the 11.75=X+6.70+4.20

==> X=11.75 - (6.70+4.20) ==> X= $0.85 is your restorqtion fees

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Answer with explanation:

The equation of two curves are

y=8 sin x

y=8 cos x

The point of intersection of two curves are

→8 sin x=8 cos x

sinx = cos x

x=\frac{\pi}{4}\\\\y=8\sin\frac{\pi}{4}\\\\y=4\sqrt{2}

When you will look between points , 0 and x=\frac{\pi}{4}\\\\y=8\sin\frac{\pi}{4}\\\\y=4\sqrt{2},the curve obtained is right angled triangle.

Now, rotate the curve that is right angled triangle along the line , y= -1, to obtain a shape similar or resembling with Right triangular prism.

Draw a circular disc in the right triangular prism , having radius =x,and small part on the triangle having length dx.dx varies from 0 to \frac{\pi}{4}.

Required volume of solid obtained

    =\int\limits^{\frac{\pi}{4}}_0 {8 \sin x} \, dx \\\\=|-8\cos x|\left \{ {{x=\frac{\pi}{4}}} \atop {x=0}} \right.\\\\=8-4\sqrt{2}

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3 years ago
Sam went 300 feet below sea level. Ken is at an elevation of 100 feet. Write an inequality to compare their location
sattari [20]
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Using technology or other resources, research the average distance that each planet is from the sun (in kilometers). Once you ha
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Answer:

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Mercury 57,909,000 Km        5.7909 X 10^3

Earth  150.33 Million Km    1.50.33 X 10^6

Mars  2.10.06 Million Km  2.1006 X 10^6

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Neptune 4.4763 Billion Km     4.4763 X 10^9

Uranus  2.5957 Billion Km         2.5957 X 10^9

Saturn  1.4936 Billion Km                  1.4936 X 10^9

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Step-by-step explanation:

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SashulF [63]
<h3><u>Answer</u>:- </h3>

\longrightarrow \sf \$ \: 307.2

<h3><u>Solution:-</u></h3>

Since painting is done on outer surface of cubical block we will have to find its surface area which is given by-

\green{ \underline { \boxed{ \sf{Surface \: area  \:of  \:Cube = 6a^2}}}}

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\begin{gathered}\\\quad \sf Surface \: area  \:of  \:Cube = 6\times(3.2)^2  \\\end{gathered}

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\sf\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad=\$ 307.2

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Answer:

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Hope This Helps! :) Please give Brainliest if it does!

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