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3 years ago

Write the equation of the line with x-intercept 3 and passing through the point (5,4).

Mathematics

1 answer:

STALIN [3.7K]3 years ago

5 0

Answer:

The equation of the line is y = 2x - 6

Step-by-step explanation:

To find the equation of this line, we first need to find the slope. To find a slope you need two ordered pairs, which you have here. The first is (5, 4) and the second is (3, 0) - which is the x-intercept of 3. Now that we have this, we can plug into the slope equation.

m(slope) = (y2 - y1)/(x2 - x1)

m = (4 - 0)/(5 - 3)

m = 4/2

m = 2

Now that we have the slope, we can use that and either point in point-slope form. Once we do that, we solve for y to get the equation.

y - y1 = m(x - x1)

y - 4 = 2(x - 5)

y - 4 = 2x - 10

y = 2x - 6

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Answer:

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Step-by-step explanation:

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3 years ago

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3 years ago

2*12 ^(n) = 49 N= exponent

Vera_Pavlovna [14]

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3 years ago

For each shipment of parts a manufacturer wants to accept only those shipments with at most 10% defective parts. A large shipmen

Stella [2.4K]

Answer:

(a) The p-value of the test statistic should be 0.33.

(b) No, there is not sufficient evidence to reject the entire shipment.

Step-by-step explanation:

We are given that for each shipment of parts a manufacturer wants to accept only those shipments with at most 10% defective parts.

A quality control manager randomly selects 50 of the parts from the shipment and finds that 6 parts are defective.

Let p = proportion of defective parts among the current shipment.

So, Null Hypothesis, $H_0$ : p $\leq$ 10% {means that the defective parts in the shipment is at most 10%}

Alternate Hypothesis, $H_A$ : p > 10% {means that the defective parts in the shipment is greater 10%}

The test statistics that would be used here One-sample z proportion statistics;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of parts that are defective among the current shipment = $\frac{6}{50}$ = 12%

n = sample of parts from the shipment = 50

So, test statistics = $\frac{0.12-0.10}{\sqrt{\frac{0.12(1-0.12)}{50} } }$

= 0.44

The value of z test statistics is 0.44.

(a) Now, P-value of the test statistics is given by the following formula;

P-value = P(Z > 0.44) = 1 - P(Z $\leq$ 0.44)

= 1 - 0.67003 = 0.3299 ≈ 0.33

(b) Since, the P-value of test statistics is more than the level of significance as 0.33 > 0.05, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the defective parts in the shipment is at most 10%.

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3 years ago