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geniusboy [140]
3 years ago
10

PQ=2x+1 and QR=5x-44 find PQ

Mathematics
1 answer:
NNADVOKAT [17]3 years ago
7 0

2x + 1 = 5x - 44

3x = 45

x = 15

Thus PQ = 2*(15) + 1 = 31

PQ = 31

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7,3,5,6 using each number only once equal 75 using parentheses
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Task: Nonpermissible Values for Rational Expressions [30 points] Write a rational expression that has the nonpermissible values
igor_vitrenko [27]

Answer:

A rational expression that has the nonpermissible values x = 0 and x = 17 is f(x) = \frac{4}{x\cdot (x-17)}.

Step-by-step explanation:

A rational expression has a nonpermissible value when for a given value of x, the denominator is equal to zero. In addition, we assume that both numerator and denominator are represented by polynomials, such that:

f(x) = \frac{p(x)}{q(x)} (1)

Then, the factorized form of q(x) must be:

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If we know that p(x) = 4, then the rational expression is:

f(x) = \frac{4}{x\cdot (x-17)} (3)

A rational expression that has the nonpermissible values x = 0 and x = 17 is f(x) = \frac{4}{x\cdot (x-17)}.

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Gnesinka [82]

Answer:

6.3333333333333333333333333333333333333333333333333333333333

Step-by-step explanation:

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Answer:

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