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klio [65]
2 years ago
7

(Picture) INFINITE SEQUENCES AND SERIES PLEASE HELP!!

Mathematics
1 answer:
mojhsa [17]2 years ago
5 0

Answer:

C) x=\frac{17}{33}

Step-by-step explanation:

0.51 repeating decimal

x= 0.51515151

multiply by 100 on both sides

100x = 51.515151.........

     x=    0.515151...............

--------------------------------------------(subtract)

   99x = 51

divide by 99 on both sides

x=\frac{51}{99}

divide both sides by 3

x=\frac{17}{33}


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A store is having a 20% off sale on all merchandise. If Mai buys one item and saves 13$, what was the original sale price of her
Montano1993 [528]

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$65 is the original price

Step-by-step explanation:

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3 years ago
A right triangle has legs measuring 16 inches and 20 inches what is the length of the hypotenuse
leonid [27]

Answer:

The length of the hypotenuse is 4\sqrt{41}\ in

Step-by-step explanation:

we know that

In a right triangle

Applying the Pythagoras Theorem

c^{2}=a^{2}+b^{2}

where

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8 0
3 years ago
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mojhsa [17]

Answer:

(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{1}{15}

Step-by-step explanation:

Given

(\frac{6}{10})^3 * (\frac{5}{9})^2

Required

Solve:

(\frac{6}{10})^3 * (\frac{5}{9})^2

Simplify 6/10

(\frac{6}{10})^3 * (\frac{5}{9})^2 = (\frac{3}{5})^3 * (\frac{5}{9})^2

Express 9 as 3^2

(\frac{6}{10})^3 * (\frac{5}{9})^2 = (\frac{3}{5})^3 * (\frac{5}{3^2})^2

Apply law of indices

(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{3^3}{5^3}* \frac{5^2}{(3^2)^2}

(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{3^3}{5^3}* \frac{5^2}{3^4}

Express as a sing;e fraction

(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{3^3*5^2}{5^3*3^4}

Apply law of indices:

(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{1}{5^{3-2}*3^{4-3}}

(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{1}{5^1*3^1}

(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{1}{5*3}

(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{1}{15}

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oee [108]
The answer is 1. X< 48.84
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