Question

If a homozygous dominant individual (Individual I) is crossed with a homozygous recessive individual (Individual II), calculate the probability that the offspring will exhibit the dominant phenotype of this pea plant gene. Assume the inheritance of this gene obeys Mendel's principle of segregation and displays Mendelian rules of dominance.

Answer 1

Answer:

100%

Explanation:

Let's assume that the genotype of the homozygous dominant individual (individual I) is "AA" and that of the homozygous recessive individual (Individual II) is "aa". A cross between AA and aa would produce all the progeny having the genotype "Aa".  

Cross: AA x aa = All Aa

Since the inheritance of gene obeys Mendel's laws of dominance and segregation, the progeny with genotype "Aa" would express the dominant trait and the recessive trait would be masked. Therefore, there is a 100% probability of getting the progeny with the dominant phenotype from the given cross.