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Juli2301 [7.4K]
3 years ago
15

In the relation defined by the equation y = x2, for all x > 0, y is a function of x because

Mathematics
1 answer:
Slav-nsk [51]3 years ago
7 0
X cannot be a negative number
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Find the arc length of the bolder arc<br> A) 283.5 mi<br> C) 733.0 mi<br> B) 10.2 mi<br> D) 73.3 mi
statuscvo [17]

Answer:

d its d :)

Step-by-step explanation:

i already did that

7 0
3 years ago
Mark bought 3 bags of pretzels for $2.00 each. He also bought 2 bottles of juice for $1.50 each. Write an expression and find th
Agata [3.3K]

Answer:

Total Cost for Pretzels and juice is $9.

Step-by-step explanation:

Given:

Number of Bags of pretzels =3

Cost for each bag = $2.00

Total Cost of Pretzels is equal to product of Number of Bags of pretzels and Cost for each bag.

Framing in equation form we get;

Total Cost of Pretzels = 3\times 2= \$6

Also Given:

Number of Bottle of Juice = 2

Price of each bottle = $1.5

Total Cost of Juice is equal to product of Number of Bottle of Juice and Price of each bottle.

Framing in equation form we get;

Total Cost of Juice = 2\times 1.5= \$3

Total Cost of Pretzels and juice is equal to sum of Total Cost of Pretzels and Total Cost of Juice.

Total Cost of Pretzels and juice = Total Cost of Pretzels + Total Cost of Juice

Total Cost of Pretzels and juice = $6 + $3 =$9

Hence Total Cost for Pretzels and juice is $9.

5 0
3 years ago
Given: \overline{AC} \cong \overline{BD}
andriy [413]
Given overtime A/C and the instructions would be DA
7 0
3 years ago
The jacks and balls have to be split among 6 people. Use the Distributive Property to pull the number 6 out of the expression yo
Nat2105 [25]

Answer: (24 + 60) = (6 × 4 + 6 × 10) = 6 × (4 + 10)

6 0
3 years ago
Solve the given initial-value problem in which the input function g(x) is discontinuous. [Hint: Solve the problem on two interva
faltersainse [42]

Step-by-step explanation:

g(x)=y''+4y\\\\y''+4y=0\\\\m^2+4=0\\m_{1,2} =+2i,-2i

so the complimentary solution is

y_{c} =c_{1} cos2x+c_{2} sin2x

solving for particular solution we get

y_{p} =acosx+bsinx

to find the values of constants a,b we put values in main equation and

-acosx-bsinx+4acosx+4bsinx=sinx\\

as g(x)=sin x

so above equation yields us

a=0,b=1/3

so writing the solution

y=y_{c} +y_{p} \\y=c_{1} cos2x+c_{2} sin2x+(1/3)sinx

using IC's to get the values for c_{1} ,c_{2}

c_{1}=1 ,c_{2} =5/6\\so\\y(x)=cos2x+(5/6)sin2x+(1/3)sinx ,0\leq x\leq \frac{\pi }{2}

solving for upper range

y(x)=\frac{2}{3} cos2x+\frac{5}{6} sin2x,x>\frac{\pi }{2}

7 0
3 years ago
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