3 years ago

In the relation defined by the equation y = x2, for all x > 0, y is a function of x because

Mathematics

1 answer:

Slav-nsk [51]3 years ago

7 0

X cannot be a negative number

You might be interested in

Is 9x to the power of 2 and 5x like terms ?

ArbitrLikvidat [17]

9x^2 and 5x are not like terms because 9x is being squared and 5x isn't.

8 0

3 years ago

Read 2 more answers

Help me pls!!!!!!!!!

Dominik [7]

Answer:

$x^2+18=-9x : x = -3, x = -6$

Step-by-step explanation:

$x^2+18=-9x$

Add 9x to both sides:

$x^2+18+9x=-9x+9x$

Simplify:

$x^2+9x+18=0$

Solve with the quadratic formula:

For a quadratic equation of the form $ax^2+bx+c=0$ the solutions are:

$x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

For $a=1,\:b=9,\:c=18:\quad x_{1,\:2}=\frac{-9\pm \sqrt{9^2-4\cdot \:1\cdot \:18}}{2\cdot \:1}$

$x =\frac{-9 + \sqrt{9^2-4\cdot \:1\cdot \:18}}{2\cdot \:1} : -3$

$x =\frac{-9 - \sqrt{9^2-4\cdot \:1\cdot \:18}}{2\cdot \:1} : -6$

The solution to the quadratic equation are:

$x=-3,\:x=-6$

Hope I helped. If so, may I get brainliest and a thanks?

Thank you, have a good day!

6 0

3 years ago

Given the angles in the diagram, who is closer to the treasure chest and why

Klio2033 [76]

Please see attached file for my answer.

Download docx

5 0

3 years ago

Read 2 more answers

For the graph shown to the right, find (a) AB to the nearest tenth and (b) the coordinates of the midpoint of AB.

Shkiper50 [21]

AB =

$\sqrt{( {4 - (- 2))}^{2} + {( - 5 + 3)}^{2} } = \sqrt{40} = 6.3$
The midpoint os segment AB =

$(( \frac{ - 2 + 4}{2} ) = the \: x \: coordinate \: of \: the \: midpoint \\ \\ ( \frac{ - 3 - 5}{2})) = the \: y \: coordinate \: of \: the \: midpoint$
The midpoint is:

(1,-4)

8 0

3 years ago

Heather has an online jewelry store . She charges $5.85 for shipping on all orders. The expression below can be used to calculat

ArbitrLikvidat [17]

Answer:23.41

Step-by-step explanation:

5 0

3 years ago