Answer:
(a) dy/dt = 68 - 3.72t
(b) 64.28m/s
Step-by-step explanation:
Given y = 68t - 1.86t²
Average Speed is rate of chance of distance with respect to time. Written as dy/dt
To obtain dy/dt, we differentiate y with respect to t, doing that, we have
dy/dt = 68 - 2(1.86)t
= 68 - 3.72t
(a) dy/dt = 68 - 3.72t
(b) To estimate the speed when t = 1, we substitute t = 1 in dy/dt .
dy/dt at t = 1 is
68 - 3.72(1)
= 68 - 3.72
= 64.28
The speed at t = 1 is 64.28m/s
Answer:
Step-by-step explanation:
I really dont know but if I did I would say I'm a 6 grader
Answer:
A. EG = √3 × FG
D. EG = √3/2 × EF
E. EF = 2 × FG
Step-by-step explanation:
∵ tan 60 = √3
∵ tan60 = EG/GF
∴ EG/GF = √3
∴ EG = √3 × GF ⇒ A
∵ m∠F = 60°
∵ sin60 = √3/2
∵ sin 60 = EG/EF
∴ √3/2 = EG/EF
∴ EG = √3/2 × EF ⇒ D
∵ cos60 = 1/2
∵ cos60 = GF/EF
∴ GF/EF = 1/2
∴ EF = 2 × GF ⇒ E
17/51=8/x <-- Cross multiply
17x=408 <-- Divide 17 by both sides
x=24
The shortest side is 24 or B.
B And c I think I don’t understand the question you’re trying to ask
