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Marrrta [24]
4 years ago
13

Solve the equation for all real solutions. 9x^2+30x+25= 0

Mathematics
1 answer:
UkoKoshka [18]4 years ago
7 0

Answer:

x = - \frac{5}{3}

Step-by-step explanation:

Given

9x² + 30x + 25 = 0 ← left side is a perfect square

(3x + 5)² = 0, thus

3x + 5 = 0 ⇒ 3x = - 5 ⇒ x = - \frac{5}{3}

solution is x = - \frac{5}{3} with multiplicity 2

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The answer should be A because when I put them on a graph they were in the shape of a square/rectangle

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3 years ago
What is the third side
ASHA 777 [7]

Answer:

A. 2.82 m

Step-by-step explanation:

<u>The missing side we are trying to find is the hypotenuse, this is because it is the longest side of a right triangle.</u>

<em><u>The Pythagorean Theorem is used:</u></em>

<em><u /></em>a^2+b^2=c^2

<em><u>Plug in the given numbers (2), accordingly:</u></em>

<em><u /></em>2^2+2^2=c^2\\4+4=c^2\\8 = c^2\\

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3 years ago
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valentina_108 [34]

Answer:

The fourth answer: A person's weight, w, on the moon is 1/6 her weight on Earth, e.

Step-by-step explanation:

The equation must be translated carefully into word form.

Her weight on Earth is represented by <em>e</em>.

"e x 1/6" into "1/6 her weight on Earth, e"

Her weight on the moon is represented by <em>w</em>.

"= w" into "A person's weight, w, on the moon is"

Another way to translate: 1/6 of a person's weight on Earth, e, is equal to her weight on the moon, w.

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3 0
3 years ago
Simplify. Your answer should contain only positive exponents with no fractional exponents in the denominator.
mart [117]

Answer:

\dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}.

Step-by-step explanation:

The given expression is  

\dfrac{3y^{\frac{1}{4}}}{4x^{-\frac{2}{3}}y^{\frac{3}{2}}\cdot 3y^{\frac{1}{2}}}

We need to simplify the expression such that answer should contain only positive exponents with no fractional exponents in the denominator.

Using properties of exponents, we get

\dfrac{3}{4\cdot 3}\cdot \dfrac{y^{\frac{1}{4}}}{x^{-\frac{2}{3}}y^{\frac{3}{2}+\frac{1}{2}}}    [\because a^ma^n=a^{m+n}]

\dfrac{1}{4}\cdot \dfrac{y^{\frac{1}{4}}}{x^{-\frac{2}{3}}y^{2}}

\dfrac{1}{4}\cdot \dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{y^{2}}         [\because a^{-n}=\dfrac{1}{a^n}]

\dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}

We can not simplify further because on further simplification we get negative exponents in numerator or fractional exponents in the denominator.

Therefore, the required expression is \dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}.

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Answer:

Step-by-step explanation:

if it is a rectangle then area=4×6=24 mm²

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3 years ago
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