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4 years ago

Solve the equation for all real solutions. 9x^2+30x+25= 0

Mathematics

1 answer:

UkoKoshka [18]4 years ago

7 0

Answer:

x = - $\frac{5}{3}$

Step-by-step explanation:

Given

9x² + 30x + 25 = 0 ← left side is a perfect square

(3x + 5)² = 0, thus

3x + 5 = 0 ⇒ 3x = - 5 ⇒ x = - $\frac{5}{3}$

solution is x = - $\frac{5}{3}$ with multiplicity 2

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The answer should be A because when I put them on a graph they were in the shape of a square/rectangle

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3 years ago

What is the third side

ASHA 777 [7]

Answer:

A. 2.82 m

Step-by-step explanation:

The missing side we are trying to find is the hypotenuse, this is because it is the longest side of a right triangle.

The Pythagorean Theorem is used:

$a^2+b^2=c^2$

Plug in the given numbers (2), accordingly:

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3 years ago

Math question help pls

valentina_108 [34]

Answer:

The fourth answer: A person's weight, w, on the moon is 1/6 her weight on Earth, e.

Step-by-step explanation:

The equation must be translated carefully into word form.

Her weight on Earth is represented by e.

"e x 1/6" into "1/6 her weight on Earth, e"

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Another way to translate: 1/6 of a person's weight on Earth, e, is equal to her weight on the moon, w.

I hope this helped :)

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3 years ago

Simplify. Your answer should contain only positive exponents with no fractional exponents in the denominator.

mart [117]

Answer:

$\dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}$ .

Step-by-step explanation:

The given expression is

$\dfrac{3y^{\frac{1}{4}}}{4x^{-\frac{2}{3}}y^{\frac{3}{2}}\cdot 3y^{\frac{1}{2}}}$

We need to simplify the expression such that answer should contain only positive exponents with no fractional exponents in the denominator.

Using properties of exponents, we get

$\dfrac{3}{4\cdot 3}\cdot \dfrac{y^{\frac{1}{4}}}{x^{-\frac{2}{3}}y^{\frac{3}{2}+\frac{1}{2}}}$ $[\because a^ma^n=a^{m+n}]$

$\dfrac{1}{4}\cdot \dfrac{y^{\frac{1}{4}}}{x^{-\frac{2}{3}}y^{2}}$

$\dfrac{1}{4}\cdot \dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{y^{2}}$ $[\because a^{-n}=\dfrac{1}{a^n}]$

$\dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}$

We can not simplify further because on further simplification we get negative exponents in numerator or fractional exponents in the denominator.

Therefore, the required expression is $\dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}$ .

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4 years ago

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Law Incorporation [45]

Answer:

Step-by-step explanation:

if it is a rectangle then area=4×6=24 mm²

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3 years ago