9514 1404 393
Answer:
a. 12 cm
b. 90°
c. 60°
Step-by-step explanation:
The relevant relationships are ...
- all sides of a rhombus have the same length
- the diagonals of a rhombus are perpendicular bisectors of each other
- the diagonals of a rhombus divide the figure into 4 congruent triangles
__
a) The perimeter, 48 cm, is the sum of four equal side lengths, so any given side is (48 cm)/4 = 12 cm.
GH = 12 cm
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b) Angle EJF is where the diagonals meet. It is a right angle.
∠EJF = 90°
__
c) Angle EFJ is the complement of the one marked, so is 30°. Angles EHJ and GHJ are congruent to that, so both are 30°. Angle EHG is the sum of those two congruent 30° angles, so is ...
∠EHG = 60°
Answer: its A or B I think its more of B than A
Well because P = 2b + 2h, then h = (P - 2b) / 2. If you plug that into the area formula, then you get A = b * [(P - 2b) /2]. Plug in your Area (30 m²) and Perimeter (34 m), then Solve. You should end up with b = 15 and h = 2.
Answer:
6.5in
Step-by-step explanation:
find the area of the shaded regions
fine the surface area of the square
A = 2×2
A = 4
find the area of the triangle
A = 1/2bh
A = 1/2×2×2.5
A = 2.5
add the areas
2.5+4 = 6.5
