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tresset_1 [31]
3 years ago
14

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used. Match each expression to its equivalent f

orm. X2 + 3x + 15 x2 + 8 x2 + 6x + 34 x2 + 16 x2 - 5x + 5 x2 - 12x + 37
Mathematics
1 answer:
Stels [109]3 years ago
8 0

Answer with explanation:

Two Quadratic expressions are said to be equivalent,if they have same zeroes.But here it has been asked about ,expression which are of the same form,means Instead of being congruent they should be similar.

   Expression                                            Equivalent Expression

1.  x²+ 3 x + 15   ----------------------                      x² + 6 x + 34

2. x² + 8            ---------------------                       x² + 16

3. x² - 5 x + 5         --------------                          x² -12 x + 37

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Hey what's the answer<br>thanks. <br>​
k0ka [10]

Step-by-step explanation:

if b+c=0

b=-c

x^b=x^-c

so

1/[2(x^b)+1]

6 0
3 years ago
Can someone help me ? Please thank you
Tom [10]
Correct answer is the 4th choice 16!!!

Hope this helps!!!
7 0
3 years ago
Help please and thank you
stiks02 [169]

First, we can see that there are four sides, and none of these equation contradict each other, so it is safe to say that <em>this is a quadrilateral</em>.

Second, all of the equations have the slope of <em>0 or undefined</em>, so it is a rectangle.

Lastly, the four points of intersection shows us that the side lengths are <em>3 and 5</em> units, so the area of it is 15 units².

7 0
3 years ago
Read 2 more answers
In triangle abc, m of acb = 90, cd is perpendicular to ab , m of acd is 60. and bd is 5 cm. find ad
weeeeeb [17]

Let us draw a picture to make the things more clear.

Attached is the image.

We have been given that

\angle acd = 60 ^{\circ}

Therefore, we have

\angle dcb =90- 60= 30 ^{\circ}

Now, in triangle bcd, we have

\tan30 = \frac{5}{cd}\\&#10;\\&#10;\frac{1}{\sqrt 3}=\frac{5}{cd}\\&#10;\\&#10;cd=5\sqrt 3

Now, in triangle acb, we have

tan 60 = \frac{ad}{5\sqrt3} \\&#10;\\&#10;\sqrt 3=  \frac{ad}{5\sqrt3}\\&#10;\\&#10;ad= 5\sqrt3 \times \sqrt 3\\&#10;\\&#10;ad= 5\times 3\\&#10;\\&#10;ad=15

Thus, ad is 15 cm.


4 0
3 years ago
Find the zeros of y = x + 6x- 4 by completing the square.
dsp73

Answer:

\large\boxed{x=-3\pm\sqrt{13}}

Step-by-step explanation:

(a+b)^2=a^2+2ab+b^2\qquad(*)\\\\\\x^2+6x-4=0\qquad\text{add 4 to both sides}\\\\x^2+2(x)(3)=4\qquad\text{add}\ 3^2=9\ \text{to both sides}\\\\\underbrace{x^2+2(x)(3)+3^2}_{(*)}=4+9\\\\(x+3)^2=13\Rightarrow x+3=\pm\sqrt{13}\qquad\text{subtract 3 from both sides}\\\\x=-3\pm\sqrt{13}

8 0
3 years ago
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