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tresset_1 [31]
3 years ago
14

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used. Match each expression to its equivalent f

orm. X2 + 3x + 15 x2 + 8 x2 + 6x + 34 x2 + 16 x2 - 5x + 5 x2 - 12x + 37
Mathematics
1 answer:
Stels [109]3 years ago
8 0

Answer with explanation:

Two Quadratic expressions are said to be equivalent,if they have same zeroes.But here it has been asked about ,expression which are of the same form,means Instead of being congruent they should be similar.

   Expression                                            Equivalent Expression

1.  x²+ 3 x + 15   ----------------------                      x² + 6 x + 34

2. x² + 8            ---------------------                       x² + 16

3. x² - 5 x + 5         --------------                          x² -12 x + 37

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The plus 1 in '1 + 2/x' is shifting this graph up from where it is rotating, but the negative 1 is subtracting the area between the y-axis and the shaded region, so that when it's flipped around, it becomes a washer.

V\:=\:\int _1^3\:\pi \left[\left(1+\frac{2}{y}\right)^2-1\right]dy,\\\\\mathrm{Take\:the\:constant\:out}:\quad \int a\cdot f\left(x\right)dx=a\cdot \int f\left(x\right)dx\\=\pi \cdot \int _1^3\left(1+\frac{2}{y}\right)^2-1dy\\\\\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx\\= \pi \left(\int _1^3\left(1+\frac{2}{y}\right)^2dy-\int _1^31dy\right)\\\\

\int _1^3\left(1+\frac{2}{y}\right)^2dy=4\ln \left(3\right)+\frac{14}{3}, \int _1^31dy=2\\\\=> \pi \left(4\ln \left(3\right)+\frac{14}{3}-2\right)\\=> \pi \left(4\ln \left(3\right)+\frac{8}{3}\right)

Our exact solution will be V = π(4In(3) + 8/3). In decimal form it will be about 22.2 however. Try both solution if you like, but it would be better to use 22.2. Your graph will just be a plot under the curve y = 2/x, the first graph.

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