I'll say the first integer is x. The next consecutive odd number would be x+2. If the sum of the odd integers is 236, the equation would be
x + (x + 2) = 236
solve for x
2x + 2 = 236
subtract 2 from each side of the equation
2x = 234
divide both sides by 2
x = 117
117 is the first odd integer. to find the other integer (x + 2), substitute 117 for x, and you have 117 + 2, which equals 119
The two consecutive odd integers that add up to 236 are 117 and 119.
The answer is 55 and 25 (25)x2=50, 50+5=(55), 55+25=80.
Log5 x=4 logx 5
Ln x/ln5=4(ln5 / ln x) logx z=ln x / ln z
least common multiple=ln5 * ln x
ln²x=4ln²5
√(ln² x)=√(4 ln²5)
ln x=2ln 5
x=e^2ln5=25
Answer: x=25.
