Answer:
(-1,2)
Step-by-step explanation:
Answer:
Melissa
Step-by-step explanation:
Melissa: 18/20
Tom: 85/100
Find the common denomenater so multiply 18*5 and 20*5
Melissa: 95/100
95>85
Melissa has the greater mark
Answer:
P=40
a + b + x = P
a = 3x
b = x + 5
substitute for b & y
3x + (x+5) + x = 40
Step-by-step explanation:
longest section 1 = a
mid length section 2 = b
shortest section 3 = x
P=40
a + b + x = P
a = 3x
b = x + 5
substitute for b & y
3x + (x+5) + x = 40
5x + 5 = 40
5x = 35
x = 7
b = 12
a = 21
Solution :
Let x be student will be left handed
P = 0.09
Using the normal approximation to binomial distribution,
a). n = 108,
μ = np = 9.72


= 2.9741
Required probability,
P(x=8) = P(7.5 < x < 8.5)


Using z table,
= P(z<-0.41)-P(z<-0.75)
= 0.3409-0.2266
= 0.1143
b). P(x=12) = P(11.5 < x < 12.5)


Using z table,
= P(z< 0.94)-P(z< 0.60)
= 0.8294 - 0.7257
= 0.1006
The average rate of change over some interval [a, b] is equal to the slope of the secant line from (a, h(a)) to (b, h(b)).
h(t) is a quadratic function, so its graph is a parabola, and in particular it's one that has a minimum of -4 when t = 2.
The secant line over an interval [a, b] will have a negative slope if the distance from a to 2 is larger than the distance from b to 2.
(A) If a = 4 and b = 5, then |a - 2| = 2 and |b - 2| = 3, so the slope and hence average rate of change is positive.
(B) If a = -1 and b = 5, then |a - 2| = 3 and |b - 2| = 3, so this ARoC is zero.
(C) If a = 0 and b = 4, then |a - 2| = 2 and |b - 2| = 2, so this ARoC is also zero.
(D) If a = -1 and b = 4, then |a - 2| = 3 and |b - 2| = 2, so this ARoC is negative.