She has found that 5 out of 7 seeds produce corn. She wants to have 10,000 corn bearing plants. How many seeds should see plant

1 answer:

3 0

It would take 70,000 seeds if five out of seven are good. So over a quantity of 50,000 plants desired, you would sow 70,000 seeds. As 20,000 would statistically fail.

You might be interested in

F(x) = { -2x -1, x ≤ 2

Degger [83]

Answer:

Use the appropriate entry method for piecewise functions for the graphing calculator of interest.

Step-by-step explanation:

For Desmos, the entry looks like ...

f(x) = {x ≤ 2: -2x-1,-x+4}

_____

For a TI-84 calculator, the entry may look like ...

Y₁ = (-2X–1)(X≤2) + (-X+4)(X>2)

The symbols ≤ and > come from the TEST menu, which is the (2nd) shift of the MATH key.

Note that the function is the sum of the pieces, each piece multiplied by a test. For something like 0≤x<2, the multiplier would be a pair of tests:

... (0≤X)(X<2)

8 0

3 years ago

A gold mine has two elevators, one for equipment and another for the miners. The equipment elevator descends 4 feet per second.

Ad libitum [116K]

Let $d_m,\ d_e$ represent the depth of the miner and equipments elevator, respectively. We know that equipment elevator descends with a velocity of $v_e = 4$ feet per second, and the miners one descends with a velocity of $v_m = 15$ feet per second.

If we start counting time ( $t=0$ ) when the equipment elevator begins to descend, after $t$ seconds its depth will be

$d_e(t) = v_et = 4t$

On the other hand, the miner elevator follows the same rule, but we have to use its velocity, and remember that it starts with a delay of thirty seconds:

$d_m(t) = v_m(t-30) = 15(t - 30)$

Now, we have to wait the 30 seconds of delay, and then another 14 seconds. This means that we want to know the positions of both elevators when $t = 44$ . Let's plug this value into the two equations: