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jeka57 [31]
4 years ago
7

Jaidee and Willie each improves their yards by planting rose bushes and geraniums. They bought their supplies from the same stor

e. Jaidee spent $84 on 3 rose bushes and 12 geraniums. Willie spent $120 on 8 rose bushes and 6 geraniums. Find the cost of one rose and the cost of one geranium
Mathematics
1 answer:
stiks02 [169]4 years ago
3 0

The cost of one rose bush is $12 and cost of one geranium is $4.

Step-by-step explanation:

Let,

Cost of one rose = x

Cost of one geranium = y

According to given statement;

3x+12y=84    Eqn 1

8x+6y=120    Eqn 2

Multiplying Eqn 2 by 2

2(8x+6y=120)\\16x+12y=240\ \ \ \ Eqn\ 3

Subtracting Eqn 1 from Eqn 3

(16x+12y)-(3x+12y)=240-84\\16x+12y-3x-12y=156\\13x=156\\

Dividing both sides by 13

\frac{13x}{13}=\frac{156}{13}\\x=12

Putting x=12 in Eqn 1

3(12)+12y=84\\36+12y=84\\12y=84-36\\12y=48

Dividing both sides by 12

\frac{12y}{12}=\frac{48}{12}\\y=4

The cost of one rose bush is $12 and cost of one geranium is $4.

Keywords: linear equation, subtraction

Learn more about subtraction at:

  • brainly.com/question/1506379
  • brainly.com/question/1522572

#LearnwithBrainly

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A box contain 12 balls in which 4 are white 3 are blue and 5 are red.3 balls are drawn at random from the box.find the chance th
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Answer:

3/11

Step-by-step explanation:

From the above question, we have the following information

Total number of balls = 12

Number of white balls = 4

Number of blue balls = 3

Number of red balls = 5

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C(n, r) = nCr = n!/r!(n - r)!

We are told that 3 balls are drawn out at random.

The chance/probability of drawing out 3 balls = 12C3 = 12!/3! × (12 - 3)! = 12!/3! × 9!

= 12 × 11 × 10 × 9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1/(3 × 2 × 1) × (9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1)

= 220 ways

The chance of selecting 3 balls at random = 220

To find the chance that all the three balls are selected,

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The chance that all three are selected is = 3/11

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4 years ago
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