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jeka57 [31]
3 years ago
7

Jaidee and Willie each improves their yards by planting rose bushes and geraniums. They bought their supplies from the same stor

e. Jaidee spent $84 on 3 rose bushes and 12 geraniums. Willie spent $120 on 8 rose bushes and 6 geraniums. Find the cost of one rose and the cost of one geranium
Mathematics
1 answer:
stiks02 [169]3 years ago
3 0

The cost of one rose bush is $12 and cost of one geranium is $4.

Step-by-step explanation:

Let,

Cost of one rose = x

Cost of one geranium = y

According to given statement;

3x+12y=84    Eqn 1

8x+6y=120    Eqn 2

Multiplying Eqn 2 by 2

2(8x+6y=120)\\16x+12y=240\ \ \ \ Eqn\ 3

Subtracting Eqn 1 from Eqn 3

(16x+12y)-(3x+12y)=240-84\\16x+12y-3x-12y=156\\13x=156\\

Dividing both sides by 13

\frac{13x}{13}=\frac{156}{13}\\x=12

Putting x=12 in Eqn 1

3(12)+12y=84\\36+12y=84\\12y=84-36\\12y=48

Dividing both sides by 12

\frac{12y}{12}=\frac{48}{12}\\y=4

The cost of one rose bush is $12 and cost of one geranium is $4.

Keywords: linear equation, subtraction

Learn more about subtraction at:

  • brainly.com/question/1506379
  • brainly.com/question/1522572

#LearnwithBrainly

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In a study of the accuracy of fast food​ drive-through orders, one restaurant had 34 orders that were not accurate among 371 ord
postnew [5]

Answer:

The claim that he rate of inaccurate orders is equal to​ 10% is supported by statistical evidnece at 5% level

Step-by-step explanation:

Given that in a study of the accuracy of fast food​ drive-through orders, one restaurant had 34 orders that were not accurate among 371 orders observed.

Sample proportion p=0.092\\q=1-p = 0.908\\n = 371

H_0: p =0.10\\H_a: p \neq 0.10

(Two tailed test at 5% significance level)

p difference = 0.092-0.100\\=-0.0084

Std error if H0 is true = \sqrt{\frac{0.1(0.9)}{371} } \\=0.016

Test statistic Z = p diff/std error

=0.539

p value = 0.5899

Since p > 0.05 accept null hypothesis

The claim that he rate of inaccurate orders is equal to​ 10% is supported by statistical evidnece at 5% level

8 0
3 years ago
Convert the integral below to polar coordinates and evaluate the integral.
Lelechka [254]

Answer:

\int\limits_{0}^{4/\sqrt{2}}\int\limits_{y}^{\sqrt{16-y^2}}  xy \, dxdy =  \int\limits_{0}^{\pi/4} \, \int\limits_{0}^{4}    r^3 cos(\theta)\sin(\theta) \,\,  drd\theta = 16

Step-by-step explanation:

We are trying to evaluate this integral.

\int\limits_{0}^{4/\sqrt{2}}\,\,\int\limits_{y}^{\sqrt{16-y^2}}  xy \,\,dxdy

The first thing that we have to do is understand this region in the plane.

\{ (x,y) \in \mathbb{R} :  0\leq y \leq \frac{4}{\sqrt{2}} \,\, , y \leq x \leq \, \sqrt{16-y^2}   \}

If you graph it looks something like the photo I join.

Now we need to describe that same region in polar coordinates.

That same region in polar coordinates would be

\{ (r,\theta) : \,\, 0 \leq \theta \leq \frac{\pi}{4}  \,\,\, 0\leq r \leq 4  \}

Now remember that when we do the polar transformation we use the following formula

\int\limits_{a}^{b} \, \int\limits_{c}^{d}    f(x,y) \,dxdy =  \int\limits_{\theta_1}^{\theta_2} \, \int\limits_{r_1}^{r_2}    r* f(rcos(\theta),rsin(\theta))  \,drd\theta

Then our integral would be

\int\limits_{0}^{4/\sqrt{2}}\int\limits_{y}^{\sqrt{16-y^2}}  xy \, dxdy =  \int\limits_{0}^{\pi/4} \, \int\limits_{0}^{4}    r^3 cos(\theta)\sin(\theta) \,\,  drd\theta = 16

6 0
3 years ago
Akira Chang's uncle dies without a will, leaving an estate of $945,000. His heirs consist of a wife and two adult children. His
OLEGan [10]
Let w represent the amount the wife receives.
.. w +2*(2/3*w) = 945,000
.. 7/3w = 945,000
.. w = (3/7)*945,000 = 405,000

The wife will receive $405,000.
5 0
3 years ago
You hear on the news that the​ S&P 500 was down 2.3 %2.3% today relative to the​ risk-free rate​ (the market's excess return
exis [7]
-25%x=466
Hope this helps you thank
6 0
3 years ago
I would like to know the answer for this question
g100num [7]
To put words into equations:
x+y+z =50
x=4y
4y=5z -> z= 4/5 y


Which means
4y+y+ 4/5 y= 50
29/5 y =50
29y=250
Y=29/250
3 0
4 years ago
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