All exercises involve the same concept, so I'll show you how to do the first, then you can apply the exact same logic to all the others.
The first thing you need to know is that, when a certain quantity multiplies a parenthesis, you can distribute that number to every element in the parenthesis. This means that

So,
is multiplying the parenthesis involving
and
, and we distributed it:
multiplies both
and
in the final result.
Secondly, you have to know how to recognize like terms, because they are the only terms you can sum. Two terms can be summed if they have the same literal expression. So, for example, you cannot sum
, and neither
exponents count.
But you can su, for example,

or

So, take for example exercise 9:

We distribute the 1.2 through the first parenthesis:

And you can distribute the negative sign through the second parenthesis (it counts as a -1 to distribute):

So, the expression becomes

Now sum like terms:

Answer:
Answer is ...Obtuse
Step-by-step explanation:








We get,
m<ABC =

Hence <ABC is obtuse
Answer:
The answer is
, or the first option.
The last option isn't correct for this answer, even though it is correct mathematically. This is because it wants the fully simplified version, so the 5o squared would turn into a 5 and a 2, with the 5 multiplying the -6, and the 2 remaining underneath the square root.
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On your papers does it say what x equals?