In a class 19 of students, 10 are female and 7 have an A in the class. There are 3 students who are male and have an A in the cl
ass. What is the probability that a student who has an A is a female?
2 answers:
Answer:7
Step-by-step explanation:
7 females have an a
Answer:
21%
Step-by-step explanation:
the total number of students is 19.
the number of students that have an A is 7.
the number of students that have an A and are a boy is 3, which leaves 4 others in the category of getting an A.
4 out of the 19 total students could be female with an A.
4/19 = 0.21 = 21%
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Answer:
=8p−7.25
Step-by-step explanation:
=(5)(p)+(5)(−1)+(3)(p)+(3)(−0.75)
=5p+−5+3p+−2.25
=5p+−5+3p+−2.25
=(5p+3p)+(−5+−2.25)
=8p+−7.25
Answer: √
10
−
75
Step-by-step explanation:
Answer:
Step-by-step explanation:
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Answer:
It's B
Step-by-step explanation:
y=mx+b
The average would be the total yards divided by the number of carries:
Rewrite 15 3/4 as 63/4
Now divide by 7:
63/4 / 7 =
63/4 x 1/7 = 63/28 = 2 1/4
Because the total yards was a loss, which would be a negative number, the average is - 2 1/4 yards per play.
