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3 years ago

Solve the right triangle shown in the figure. Remember, exact lengths can be approximated on a calculator. For

Mathematics

1 answer:

krek1111 [17]3 years ago

3 0

Answer: B is correct

Step-by-step explanation:

Edg 2021

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Slope of 4/5, a width of 30…what is the height..?

maw [93]

$\qquad\qquad\huge\underline{{\sf Answer}}$

Here we go ~

Slope of the graph can be expressed as :

$\qquad \sf \dashrightarrow \:slope = \tan( \theta) = \dfrac{4}{5}$

$\qquad \sf \dashrightarrow \: \dfrac{x}{30} = \dfrac{4}{5}$

$\qquad \sf \dashrightarrow \: x = \dfrac{4}{5} \times 30$

$\qquad \sf \dashrightarrow \: x = {4}{} \times 6$

$\qquad \sf \dashrightarrow \: x = 24 \: units$

So, the value of x is 24 units

8 0

1 year ago

Find the value of x in the following parallelogram: 3 5x - 6 3x - 2 x = [?]

Rufina [12.5K]

3x-2 = 5x-6

3x-5x = -6+2

-2x = -4

x = 2

8 0

2 years ago

Read 2 more answers

Somebody please help!!!!!!!!

Jlenok [28]

Answer:

I think the answer is b^2=8^2-4^2

Step-by-step explanation:

The equation is A^2+B^2=C^2

C^2-A^2=B^2

C^2-B^2=A^2

C is the hypotenuse. You know what a is and all you have to do is show the equation

3 0

3 years ago

Read 2 more answers

A student has gotten the following grades on his tests. What is the minimum grade he must get on the last test in order to have

arsen [322]

The lowest grade that student could get is a 91 or higher

7 0

3 years ago

An athlete knows that when she jogs along her neighborhood greenway, she can complete the route in 10 minutes. It takes 20 minu

IgorLugansk [536]

Answer:

10 miles per hour.

Step-by-step explanation:

Let x represent athlete's walking speed.

We have been given that her jogging rate is 5 mph faster than her walking rate, so athlete's jogging speed would be $x+5$ miles per hour.

$\text{Distance}=\text{Rate}\cdot \text{Time}$

10 minutes = 1/6 hour.

20 minutes = 1/3 hour

While walking, we will get $D_{\text{walking}}=x\frac{\text{miles}}{\text{hour}}\cdot \frac{1}{3}\text{hour}$

$D_{\text{walking}}=\frac{x}{3}$

While jogging, we will get $D_{\text{jogging}}=(x+5)\frac{\text{miles}}{\text{hour}}\cdot \frac{1}{6}\text{hour}$

$D_{\text{jogging}}= \frac{(x+5)}{6}$

Since athlete is covering same distance while walking and jogging, so we can equate both expressions as:

$\frac{x}{3}=\frac{x+5}{6}$

Cross multiply:

$6x=3x+15$

$6x-3x=15$

$3x=15$

$\frac{3x}{3}=\frac{15}{3}\\\\x=5$

Therefore, athlete's walking speed is 5 miles per hour.

Jogging speed: $x+5\Rightarrow 5+5=10$

Therefore, athlete's jogging speed is 10 miles per hour.

3 0

3 years ago