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Fiesta28 [93]
3 years ago
5

Solve for A ? Anyone willing to help me :)

Mathematics
1 answer:
GrogVix [38]3 years ago
5 0

Answer:

<h2>2.2</h2>

Step-by-step explanation:

Use the cosine law:

BC^2=AB^2+AC^2-2(AB)(AC)\cos(\angle A)

We have:

BC=a\\\\AB=4\\\\AC=3\\\\m\angle A=32^o\to\cos32^o\approx0.848

Substitute:

a^2=4^2+3^2-2(4)(3)(0.848)\\\\a^2=16+9-20.352\\\\a^2=4.648\to a=\sqrt{4.648}\\\\a\approx2.2

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EMERGENCY PLEASE HELP STRUGGLING! The triangles in each pair are similar.
Ludmilka [50]

Answer: The missing length is 120 {option C}

Step-by-step explanation: What we have in the question is a triangle placed on top of another triangle and as shown in the attached diagram we can separate them into triangles BFC and GFH.

A close observation shows that line BC is parallel to line GH. Hence we have two similar triangles, and we can determine their similarity ratios as follows;

BF/FC = GF/FH

Similarly BF/BC = GF/GH

We can also express the following ratio

FC/FH = BC/GH

Therefore to calculate the missing side, which is GF, we can use the ratio

FC/FH = FB/FG

30/100 = 36/FG

By cross multiplication we now have 30 (FG) = 100 (36)

30FG = 3600

Divide both sides of the equation by 30

FG = 120

5 0
3 years ago
An article describes a study comparing two methods of measuring mean arterial blood pressure. The auscultatory method is based o
zzz [600]

Answer:

p_v =P(t_{(5)}>0.499) =0.319

The p value is higher than any significance level given for example \alpha=0.05,0.1, so then we can conclude that we FAIL to reject the null hypothesis. So we don't have enough evidence to conclude that the mean reading is greater for the auscultatory method at 5% or 10% of significance.

Step-by-step explanation:

A paired t-test is used to compare two population means where you have two samples in  which observations in one sample can be paired with observations in the other sample. For example  if we have Before-and-after observations we can use it.  

Let put some notation  

x=Auscultatory method , y = Oscillatory method

x: 74 86 84 79 70 78 79 70

y: 70 85 90 110 71 80 69 74

The system of hypothesis for this case are:

Null hypothesis: \mu_x- \mu_y \leq 0

Alternative hypothesis: \mu_x -\mu_y >0

The first step is define the difference d_i=x_i-y_i, that is given so we have:

d: 6.6, 4.2, -5.5, -3.1, 9.3, -3.9

The second step is calculate the mean difference  

\bar d= \frac{\sum_{i=1}^n d_i}{n}=1.267

The third step would be calculate the standard deviation for the differences, and we got:

s_d =\sqrt{\frac{\sum_{i=1}^n (d_i -\bar d)^2}{n-1}} =6.215

The fourth step is calculate the statistic given by :

t=\frac{\bar d -0}{\frac{s_d}{\sqrt{n}}}=\frac{1.267 -0}{\frac{6.215}{\sqrt{6}}}=0.499

The next step is calculate the degrees of freedom given by:

df=n-1=6-1=5

Now we can calculate the p value, since we have a right tailed test the p value is given by:

p_v =P(t_{(5)}>0.499) =0.319

The p value is higher than any significance level given for example \alpha=0.05,0.1, so then we can conclude that we FAIL to reject the null hypothesis. So we don't have enough evidence to conclude that the mean reading is greater for the auscultatory method at 5% or 10% of significance.

5 0
3 years ago
Can someone help me with this problem?
pashok25 [27]
No, it is not a solution.

Let's plug 5 into the equation where p is.

10(5) - 2 > 97

50 - 2 > 97

48 > 97

This is false, 48 is less than 97.
7 0
3 years ago
Read 2 more answers
What are the TWO ways you chose to display the data?
Setler [38]
I use indicators and line charts
6 0
3 years ago
What is the sum of two numbers is 45 and theire difference is 5
adelina 88 [10]

Answer:

let the two numbers be x and y

x+y=45(equation 1)

x-y=5(equation 2)

from equation (1) y=45-x(equation 3)

substitute 45-x for y in equation 2

x-(45-x)=5

x-45+x=5

x+x-45=5

2x-45=5

2x=45+5

2x=50

x=50/2

x=25

6 0
3 years ago
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