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3 years ago

How old am I if 2 times my age increased by 244 is 400?

Mathematics

2 answers:

ikadub [295]3 years ago

8 0

Answer:

Step-by-step explanation:

400-244=156

156/2=78

MrRissso [65]3 years ago

7 0

Answer:

78 years old

Step-by-step explanation:

400 − 2 x = 244

400 − 244 = 2 x

156 = 2 x

so the answer would be 78 years old...

Hope that was helpful.Thank you!!!

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Find an equation of the line passing through the point (2, -3) and has slope -4. Then rewrite your linear equation in the slope-

Tresset [83]

Answer:

y=-4x+5

Step-by-step explanation:

y+3=-4(x-2)

y+3=-4x+8

-3. -3

y=-4x+5

8 0

3 years ago

A point H is 20m away from the foot of a tower on the same horizontal ground. From the point H, the angle of elevation of the po

astra-53 [7]

Answer:

a. See Attachment 1

b. $PT = 12.3\ m$

c. $HT = 31.1\ m$

d. $OH = 28.4\ m$

Step-by-step explanation:

Calculating PT

To calculate PT, we need to get distance OT and OP

Calculating OT;

We have to consider angle 50, distance OH and distance OT

The relationship between these parameters is;

$tan50 = \frac{OT}{20}$

Multiply both sides by 20

$20 * tan50 = \frac{OT}{20} * 20$

$20 * tan50 = OT$

$20 * 1.1918 = OT$

$23.836 = OT$

$OT = 23.836$

Calculating OP;

We have to consider angle 30, distance OH and distance OP

The relationship between these parameters is;

$tan30 = \frac{OP}{20}$

Multiply both sides by 20

$20 * tan30 = \frac{OP}{20} * 20$

$20 * tan30 = OP$

$20 * 0.5774= OP$

$11.548 = OP$

$OP = 11.548$

$PT = OT - OP$

$PT = 23.836 - 11.548$

$PT = 12.288$

$PT = 12.3\ m$ (Approximated)

--------------------------------------------------------

Calculating the distance between H and the top of the tower

This is represented by HT

HT can be calculated using Pythagoras theorem

$HT^2 = OT^2 + OH^2$

Substitute 20 for OH and $OT = 23.836$

$HT^2 = 20^2 + 23.836^2$

$HT^2 = 400 + 568.154896$

$HT^2 = 968.154896$

Take Square Root of both sides

$HT = \sqrt{968.154896}$

$HT = 31.1\ m$ <em>(Approximated)</em>

--------------------------------------------------------

Calculating the position of H

This is represented by OH

See Attachment 2

We have to consider angle 50, distance OH and distance OT

The relationship between these parameters is;

$tan50 = \frac{OH}{OT}$

Multiply both sides by OT

$OT * tan50 = \frac{OH}{OT} * OT$

$OT * tan50 = {OH$

$OT * 1.1918 = OH$

Substitute $OT = 23.836$

$23.836 * 1.1918 = OH$

$28.4= OH$

$OH = 28.4\ m$ <em> (Approximated)</em>

5 0

3 years ago

How do I solve these problems?

lesya [120]

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3 years ago

What is the solution to the system of equations? Use any method. {y=−3x+1 {2x+5y=18

Softa [21]

Answer:

So the solution set of the equations are {(-1,4)}

the solution is x = -1 and y = 4

Step-by-step explanation:

Equations given to us are

y = -3x + 1 ..................(i)

2x + 5y = 18 .................(ii)

To find the value of x and y or the solution set of the system of equations

Now in first equation we see that

y = -3x + 1

Putting this value in equation (ii)

which is

2x + 5y = 18

Putting value of y from (i) in it

2x + 5(-3x + 1) = 18

Opening the bracket and multiplying inside

2x -15x + 5 = 18

-13 x + 5 = 18

Subtracting 5 from both sides of the equation

-13x + 5 - 5 = 18 -5

-13x = 13

Dividing both sides by -13

$\frac{-13x}{-13}=\frac{13}{-13}$

Cutting out the same values gives us

x = -1

For value of y

putting value of x in equation (i)

which is

y = -3x + 1

Putting the value

y = -3(-1)+1

y=3+1

y=4

So the solution set of the equations are {(-1,4)}

the solution is x = -1 and y = 4

4 0

4 years ago

(AC)^2 = (5)^2 + (11)^2 - (2*5*11*Cos 125º)

Arada [10]

Answer: (11)^2

Step-by-step explanation:

HOW ARE WE ANSWER THAT?

5 0

3 years ago