Ask question

Ask question

All categories

3 years ago

11

ASAP TODAY MY B-DAY HELP ME AS A PRESNT PLZZZZZZZZZZZZZZZZZZZ7. The cost of a telephone call is $0.75 + $0.25 times the number o

f minutes. Write an algebraic
expression that models the cost of a telephone call that lasts t minutes.

1 answer:

katrin [286]3 years ago

3 0

Answer:

0.75 + 0.25 = t

You might be interested in

The manufacturer of an energy drink spends $1.20 to make each drink and sells them for $2. The manufacturer also has fixed costs

Yuki888 [10]

What is the question?

8 0

2 years ago

What is the answer to this question really need the answer

jeyben [28]

Answer:

A, B, D

Step-by-step explanation:

2 x 3x =6x - 2 times 9y which equals 18y+ and 2 times 18 equals 36 so 2(3x-9y+18)

3 0

3 years ago

The expression (secx + tanx)2 is the same as _____.

trapecia [35]

<u>Answer:</u>

The expression $\bold{(\sec x+\tan x)^{2} \text { is same as } \frac{1+\sin x}{1-\sin x}}$

<u>Solution:</u>

From question, given that $\bold{(\sec x+\tan x)^{2}}$

By using the trigonometric identity $(a + b)^{2} = a^{2} + 2ab + b^{2}$ the above equation becomes,

$(\sec x+\tan x)^{2} = \sec ^{2} x+2 \sec x \tan x+\tan ^{2} x$

We know that $\sec x=\frac{1}{\cos x} ; \tan x=\frac{\sin x}{\cos x}$

$(\sec x+\tan x)^{2}=\frac{1}{\cos ^{2} x}+2 \frac{1}{\cos x} \frac{\sin x}{\cos x}+\frac{\sin ^{2} x}{\cos ^{2} x}$

$=\frac{1}{\cos ^{2} x}+\frac{2 \sin x}{\cos ^{2} x}+\frac{\sin ^{2} x}{\cos ^{2} x}$

On simplication we get

$=\frac{1+2 \sin x+\sin ^{2} x}{\cos ^{2} x}$

By using the trigonometric identity $\cos ^{2} x=1-\sin ^{2} x$ ,the above equation becomes

$=\frac{1+2 \sin x+\sin ^{2} x}{1-\sin ^{2} x}$

By using the trigonometric identity $(a+b)^{2}=a^{2}+2ab+b^{2}$

we get $1+2 \sin x+\sin ^{2} x=(1+\sin x)^{2}$

$=\frac{(1+\sin x)^{2}}{1-\sin ^{2} x}$

$=\frac{(1+\sin x)(1+\sin x)}{1-\sin ^{2} x}$

By using the trigonometric identity $a^{2}-b^{2}=(a+b)(a-b)$ we get $1-\sin ^{2} x=(1+\sin x)(1-\sin x)$

$=\frac{(1+\sin x)(1+\sin x)}{(1+\sin x)(1-\sin x)}$

$= \frac{1+\sin x}{1-\sin x}$

Hence the expression $\bold{(\sec x+\tan x)^{2} \text { is same as } \frac{1+\sin x}{1-\sin x}}$

8 0

3 years ago

-3(8)+5y=-24 using elimination

Step2247 [10]

Answer:

y=0

Step-by-step explanation:

-3(8) + 5y = -24

-24 + 5y = -24

y=0

5 0

3 years ago

Read 2 more answers

Find the surface area of the rectangular prism. 5ft tall 5 feet long 2 feet wide

Mars2501 [29]

Answer:

46.25 feet squared

Step-by-step explanation:

base area = 5x2 = 10

you need to find how tall the faces of the prism are now. You can do this using the pythagorean theorem: a^2+b^2=c^2

5^2+2.5^2=c^2 and 5^2+1^2=c^2

(since it is a rectangular pyramid)

c= 5.60 and c= 5.01

now be can find the surface area of the 4 triangles

SA= 5.60x2 and SA= 5.01x5

SA=11.2 and SA= 25.05

add all the components (11.2, 25.05, 10) together to get the final surface area: 46.25

6 0

3 years ago