When your measuring a possibility of two different outcomes
Although the number of new wildflowers is decreasing, the total number of flowers is increasing every year (assuming flowers aren't dying or otherwise being removed). Every year, 25% of the number of new flowers from the previous year are added.
The sigma notation would be:
∑ (from n=1 to ∞) 4800 * (1/4)ⁿ , where n is the year.
Remember that this notation should give us the sum of all new flowers from year 1 to infinite, and the values of new flowers for each year should match those given in the table for years 1, 2, and 3
This means the total number of flowers equals:
Year 1: 4800 * 1/4 = 1200 ]
+
Year 2: 4800 * (1/4)² = 300
+
Year 3: 4800 * (1/4)³ = 75
+
Year 4: 4800 * (1/4)⁴ = 18.75 = ~19 (we can't have a part of a flower)
+
Year 5: 4800 * (1/4)⁵ = 4.68 = ~ 5
+
Year 6: 4800 * (1/4)⁶ = 1.17 = ~1
And so on. As you can see, it in the years that follow the number of flowers added approaches zero. Thus, we can approximate the infinite sum of new flowers using just Years 1-6:
1200 + 300 + 75 + 19 + 5 + 1 = 1,600
Answer: E - S = (-16 and 6)
Step-by-step explanation:1/3 of the 30 decimals in T have an even tenths digit, it follows that 1/3*(30)=10 decimals in T have an even tenths digit.
Hence: Te =list of 10 decimals
Se = sum of all 10 decimals in Te
Ee =estimated sum of all 10 decimals in Te after rounding up.
Remaining 20 decimals in T all have an odd tenths digits.
To =list of this 20 decimals
So = sum of all 20 decimals in To
Eo = estimated sum of 20 decimals in To
Hence,
E = Ee + Eo and S =Se +So, hence:
E-S, =(Ee+Eo) - (Se+So) =(Ee-Se) +(Eo-So)
Ee-Se >10 (0.1)=1
S=10(1.8)+20(1.9) =18+38=56
E=10(2)+20(1)=40
E-S =40-56=-16.
AlsoS=10(1.2)+20(1.1)=34
E=10(2)+20(1)=40
E-S=40-34=6
<h3><u>Given Information :</u></h3>
- Length of parallel sides = 60 ft and 40 ft
- Height of the trapezoid = 30 ft
<h3><u>To calculate :</u></h3>
<h3><u>Calculation :</u></h3>
As we know that,

- a and b are length of parallel sides.
- h denotes height.
<em>S</em><em>u</em><em>b</em><em>s</em><em>t</em><em>i</em><em>t</em><em>u</em><em>t</em><em>i</em><em>n</em><em>g</em><em> </em><em>valu</em><em>es</em><em>,</em><em> </em><em>we</em><em> </em><em>get</em><em> </em>:
Area =
× ( 60 + 40 ) × 30 ft
Area =
× 100 × 30 ft
Area = 1 × 100 × 15 ft
Area = 100 × 15 ft
<u>Area = 1500 ft</u>
Therefore,
- Area of the trapezoid is <u>1500 ft
</u>
V57 v3 is Keats becuase it’s math and not why it’s not math it’s math just holy math with gif