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3 years ago

Can I get some help?

Mathematics

1 answer:

Gnom [1K]3 years ago

7 0

The equation of the straight line is y=mx+q where q is the number on the y-axis where the line passes, as you can see it is -3. It turns into:
y=mx+(-3) -> y=mx-3
Then consider a point on the line and take the coordinates, such as the point with coordinates (-2;-4), so now you know that:
x=-2 and y=-4
At this point you put these values into the equation:
y=mx-3
-4=m(-2)-3
then solve:
-4=-2m-3
-2m=+3-4
-2m=-1
m=+1/2
Put the value of m into the equation and you found it:
y=1/2x-3

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Answers fast please. 1.) y=x−63x+2y=8 Use the substitution method. A.) (4, −2) B.) (14, 8) C.) (0, −6) D.) (3, −3) 2.) What is t

GrogVix [38]

QUESTION 1

The given system of equation is

$y=x-6...eqn1$

and

$3x+2y=8...eqn2$

Let us substitute equation (1) into equation (2) to get,

$3x+2(x-6)=8$

We expand the bracket to get,

$3x+2x-12=8$

We simplify to get.

$5x-12=8$

We group like terms to get

$5x=8+12$

$\Rightarrow 5x=20$

$\Rightarrow x=4$

We now substitute $x=4$ in to equation (1) to obtain,

$y=4-6=-2$

The correct answer is option A.

QUESTION 2

The given system of equations is

$y-x=9...eqn1$

and

$10+2x=-2y...eqn2$

We make y the subject in equation (2) to get,

$y=-x-5..eqn3$

We put equation (3) into equation (1) to obtain,

$-x-5-x=9$

We group like terms to get,

$-x-x=9+5$

This implies that,

$-2x=14$

We divide through by $-2$ to get,

$x=-7$

Hence the x-coordinate is $-7$

QUESTION 3

The given system is

$y=3x-1..eqn1$

and

$x-y=-9...eqn2$

We make $x$ the subject in equation (2) to get,

$x=y-9...eqn3$

We put equation (3) into equation (1) to obtain,

$y=3(y-9)-1$

We expand the bracket to get,

$y=3y-27-1$

Group like terms to get,

$y-3y=-27-1$

We simplify to get;

$-2y=-28$

This implies that,

$y=14$

Therefore the y-coordinate is 14.

4 0

3 years ago

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Find the midpoint of the line segment

strojnjashka [21]

Answer:

midpoint (5,4)

Step-by-step explanation:

The midpoint(M) of a segment with endpoints (x₁ , y₁) and ( x₂, y₂) is

where x₁ = 2 and x₂ = 8

y₁ = 0 and y₂ = 8

M = $\frac{x_1 + x_2}{2} ,\frac{y_1 + y_2}{2}$

M = $\frac{2 + 8}{2} ,\frac{0 + 8}{2}$

M = 5 , 4

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2 years ago

PLZ HELP ASAP Geometry help: 2x^2 + 2y^2 - 8x +10y +2=0

Alexxx [7]

Ok so this is conic sectuion
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2(x^2-4x+4-4)+2(y^2+5y+6.25-6.25)+2=0
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2(x-2)^2-8+2(y+2.5)^2-12.5+2=0
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add 18.5 both sides
2(x-2)^2+2(y+2.5)^2=18.5
divide both sides by 2
(x-2)^2+(y+2.5)^2=9.25

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2 years ago

Solving simular triangles advanced

Reptile [31]

Answer:

x = 3/2

Step-by-step explanation:

We can use ratios to solve

6 6+x

-------- = -----------

4 5

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6*5 = 4 * (6+x)

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30 -24 = 24+4x-24

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Can I get some help?​

Can I get some help?