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2 years ago

If the ratio of milk cartons to juice boxes is 13:x and there are 39 milk cartons

Mathematics

2 answers:

max2010maxim [7]2 years ago

8 0

The answer is 6 because 39/13=3 and 18/3=6

Galina-37 [17]2 years ago

5 0

Answer:

Step-by-step explanation:

Just write the amount of milk cartons and juice cartons as a fraction and simplify it

39/18 the biggest common divisor for this is 3 so we divide the fraction by 3

13/6 x = 6

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2 years ago

Many utility companies promote energy conservation by offering discount rates to consumers who keep their energy usage below cer

aleksley [76]

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a. 0.1681 = 16.81% probability that all five qualify for the favorable rate.

b. 0.5283 = 52.83% probability that at least four qualify for the favorable rates

Step-by-step explanation:

For each Puerto Rico resident, there are only two possible outcomes. Either they qualify for discounted rates, or they do not. The probability of a person in the sample qualifying for discounted rates is independent of any other person in the sample. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

70% of the island residents of Puerto Rico have reduced their electricity usage sufficiently to qualify for discounted rates.

This means that $p = 0.7$

Five residential subscribers are randomly selected from San Juan, Puerto Rico

This means that $n = 5$

a. All five qualify for the favorable rate

This is P(X = 5). So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 5) = C_{5,5}.(0.7)^{5}.(0.3)^{0} = 0.1681$

0.1681 = 16.81% probability that all five qualify for the favorable rate.

b. At least four qualify for the favorable rates

This is

$P(X \geq 4) = P(X = 4) + P(X = 5)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 4) = C_{5,4}.(0.7)^{4}.(0.3)^{1} = 0.3602$

$P(X = 5) = C_{5,5}.(0.7)^{5}.(0.3)^{0} = 0.1681$

$P(X \geq 4) = P(X = 4) + P(X = 5) = 0.3602 + 0.1681 = 0.5283$

0.5283 = 52.83% probability that at least four qualify for the favorable rates

5 0

3 years ago

Which Two Numbers Add Up To Negative 26 And Multiply To 11?

Fynjy0 [20]

Xy=11
x+y=-26

x+y=-26
minus x both sides
y=-26-x

sub for y
x(-26-x)=11
-26x-x^2=11
add 26x+x^2 both sides
x^2+26x+11=0

ax^2+bx+c=0
x= $\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}$

a=1
b=26
c=11

x= $\frac{-26+/-\sqrt{26^{2}-4(1)(11)} }{2(1)}$
x= $\frac{-26+/-\sqrt{676-44} }{2}$
x= $\frac{-26+/-\sqrt{632} }{2}$
x= $\frac{-26+/-2\sqrt{158} }{2}$
x= $-13+/-\sqrt{158}$

x= $-13+\sqrt{158}$ or $-13-\sqrt{158}$

aprox

x=-0.420195 or -25.5698

those are the numbers

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3 years ago