De Moivre's theorem uses this general formula z = r(cos α + i<span> sin α) that is where we can have the form a + bi. If the given is raised to a certain number, then the r is raised to the same number while the angles are being multiplied by that number.
For 1) </span>[3cos(27))+isin(27)]^5 we first apply the concept I mentioned above where it becomes
[3^5cos(27*5))+isin(27*5)] and then after simplifying we get, [243 (cos (135) + isin (135))]
it is then further simplified to 243 (-1/ √2) + 243i (1/√2) = -243/√2 + 243/<span>√2 i
and that is the answer.
For 2) </span>[2(cos(40))+isin(40)]^6, we apply the same steps in 1)
[2^6(cos(40*6))+isin(40*6)],
[64(cos(240))+isin(240)] = 64 (-1/2) + 64i (-√3 /2)
And the answer is -32 -32 √3 i
Summary:
1) -243/√2 + 243/√2 i
2)-32 -32 √3 i
Answer:
A
Step-by-step explanation:
4^3+7=4^10
I am orearte sure the correct answer is 280 please give me brainliest if u can
Hi, so first u have to multiple 12×6=72 then next u divide by 2 which must five u a food start
Answer:
The y intercept is (0,5)
Step-by-step explanation:
f(x) = 5 * (1/6)^x
What is the y intercept? Let x = 0
f(0) = 5 * (1/6)^0
f(0) = 5*1 = 0
The y intercept is (0,5)
